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The reaction of cyanamide, NH2CN with different was carried out in a bomb calorimeter and ΔU was found to be -742.7 kJ/mol at 298K. Calculate enthalpy change for the reaction at 298K NH2CN 3/2 O2 -> N2 CO2 H2O?
Most Upvoted Answer
The reaction of cyanamide, NH2CN with different was carried out in a b...
Use deltaH=deltaU +deltaNRT....and find deltaN from rxn by subtracting number of moles of gaseous reactant from moles of gaseous product
Community Answer
The reaction of cyanamide, NH2CN with different was carried out in a b...
Understanding the Reaction
The combustion of cyanamide (NH2CN) can be represented as follows:
Reaction:
NH2CN + 3/2 O2 -> N2 + CO2 + H2O
In this case, the internal energy change (ΔU) of the reaction is given as -742.7 kJ/mol at 298 K.
Calculating Enthalpy Change
To find the enthalpy change (ΔH) from the internal energy change (ΔU), we can use the following relationship:
Formula:
ΔH = ΔU + ΔnRT
Where:
- Δn = change in the number of moles of gas
- R = universal gas constant (approximately 8.314 J/(mol·K))
- T = temperature in Kelvin (298 K)
Determining Δn
1. Reactants:
- 1 mole of NH2CN (solid)
- 1.5 moles of O2 (gas)
- Total = 1.5 moles of gas
2. Products:
- 1 mole of N2 (gas)
- 1 mole of CO2 (gas)
- 1 mole of H2O (gas)
- Total = 3 moles of gas
3. Calculating Δn:
Δn = moles of products - moles of reactants
Δn = 3 - 1.5 = 1.5 moles
Calculating ΔH
Now substituting Δn, R, and T into the equation:
ΔH = -742.7 kJ/mol + (1.5 moles)(8.314 J/(mol·K))(298 K)
Convert Joules to kJ:
ΔH = -742.7 kJ/mol + (1.5 * 8.314 * 298)/1000
Calculate and simplify to find ΔH.
Conclusion
The final value will give you the enthalpy change for the combustion of cyanamide at 298 K. Remember to check your units and calculations for accuracy!
The combustion of cyanamide (NH2CN) can be represented as follows:
Reaction:
NH2CN + 3/2 O2 -> N2 + CO2 + H2O
In this case, the internal energy change (ΔU) of the reaction is given as -742.7 kJ/mol at 298 K.
Calculating Enthalpy Change
To find the enthalpy change (ΔH) from the internal energy change (ΔU), we can use the following relationship:
Formula:
ΔH = ΔU + ΔnRT
Where:
- Δn = change in the number of moles of gas
- R = universal gas constant (approximately 8.314 J/(mol·K))
- T = temperature in Kelvin (298 K)
Determining Δn
1. Reactants:
- 1 mole of NH2CN (solid)
- 1.5 moles of O2 (gas)
- Total = 1.5 moles of gas
2. Products:
- 1 mole of N2 (gas)
- 1 mole of CO2 (gas)
- 1 mole of H2O (gas)
- Total = 3 moles of gas
3. Calculating Δn:
Δn = moles of products - moles of reactants
Δn = 3 - 1.5 = 1.5 moles
Calculating ΔH
Now substituting Δn, R, and T into the equation:
ΔH = -742.7 kJ/mol + (1.5 moles)(8.314 J/(mol·K))(298 K)
Convert Joules to kJ:
ΔH = -742.7 kJ/mol + (1.5 * 8.314 * 298)/1000
Calculate and simplify to find ΔH.
Conclusion
The final value will give you the enthalpy change for the combustion of cyanamide at 298 K. Remember to check your units and calculations for accuracy!
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The reaction of cyanamide, NH2CN with different was carried out in a bomb calorimeter and ΔU was found to be -742.7 kJ/mol at 298K. Calculate enthalpy change for the reaction at 298K NH2CN 3/2 O2 -> N2 CO2 H2O?
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The reaction of cyanamide, NH2CN with different was carried out in a bomb calorimeter and ΔU was found to be -742.7 kJ/mol at 298K. Calculate enthalpy change for the reaction at 298K NH2CN 3/2 O2 -> N2 CO2 H2O? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The reaction of cyanamide, NH2CN with different was carried out in a bomb calorimeter and ΔU was found to be -742.7 kJ/mol at 298K. Calculate enthalpy change for the reaction at 298K NH2CN 3/2 O2 -> N2 CO2 H2O? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The reaction of cyanamide, NH2CN with different was carried out in a bomb calorimeter and ΔU was found to be -742.7 kJ/mol at 298K. Calculate enthalpy change for the reaction at 298K NH2CN 3/2 O2 -> N2 CO2 H2O?.
The reaction of cyanamide, NH2CN with different was carried out in a bomb calorimeter and ΔU was found to be -742.7 kJ/mol at 298K. Calculate enthalpy change for the reaction at 298K NH2CN 3/2 O2 -> N2 CO2 H2O? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The reaction of cyanamide, NH2CN with different was carried out in a bomb calorimeter and ΔU was found to be -742.7 kJ/mol at 298K. Calculate enthalpy change for the reaction at 298K NH2CN 3/2 O2 -> N2 CO2 H2O? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The reaction of cyanamide, NH2CN with different was carried out in a bomb calorimeter and ΔU was found to be -742.7 kJ/mol at 298K. Calculate enthalpy change for the reaction at 298K NH2CN 3/2 O2 -> N2 CO2 H2O?.
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