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In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine): [NEET Kar. 2013]
- a)X2Cl
- b)X2Cl2
- c)XCl2
- d)XCl4
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
In an experiment it showed that 10 mL of 0.05 M solution of chloride r...
Millimoles of solution of chloride = 0.05 × 10 = 0.5
Millimoles of AgNO3 solution = 10 × 0.1 = 1
So, the millimoles of AgNO3 are double than the chloride solution
Millimoles of AgNO3 solution = 10 × 0.1 = 1
So, the millimoles of AgNO3 are double than the chloride solution
Most Upvoted Answer
In an experiment it showed that 10 mL of 0.05 M solution of chloride r...
Given:
- Volume of chloride solution = 10 mL
- Concentration of chloride solution = 0.05 M
- Volume of AgNO3 solution = 10 mL
- Concentration of AgNO3 solution = 0.1 M
To find: Formula of the chloride
Solution:
1. Write the balanced chemical equation for the reaction between chloride and AgNO3:
Cl- + Ag+ → AgCl
2. Calculate the number of moles of AgNO3 used:
Moles of AgNO3 = concentration x volume
Moles of AgNO3 = 0.1 x (10/1000) = 0.001 mol
3. Use the mole ratio from the balanced equation to find the number of moles of chloride:
1 mol AgNO3 : 1 mol Cl-
0.001 mol AgNO3 : 0.001 mol Cl-
4. Calculate the concentration of the chloride solution:
Concentration = moles/volume
Concentration = 0.001/(10/1000) = 0.1 M
5. Based on the concentration and formula of the chloride, determine the formula of the compound:
- The concentration of the chloride is 0.1 M.
- The formula of the compound contains one chloride ion (Cl-).
- Therefore, the formula of the compound is XCl2, where X is the symbol of the element other than chlorine.
Hence, the correct answer is option 'C' XCl2.
- Volume of chloride solution = 10 mL
- Concentration of chloride solution = 0.05 M
- Volume of AgNO3 solution = 10 mL
- Concentration of AgNO3 solution = 0.1 M
To find: Formula of the chloride
Solution:
1. Write the balanced chemical equation for the reaction between chloride and AgNO3:
Cl- + Ag+ → AgCl
2. Calculate the number of moles of AgNO3 used:
Moles of AgNO3 = concentration x volume
Moles of AgNO3 = 0.1 x (10/1000) = 0.001 mol
3. Use the mole ratio from the balanced equation to find the number of moles of chloride:
1 mol AgNO3 : 1 mol Cl-
0.001 mol AgNO3 : 0.001 mol Cl-
4. Calculate the concentration of the chloride solution:
Concentration = moles/volume
Concentration = 0.001/(10/1000) = 0.1 M
5. Based on the concentration and formula of the chloride, determine the formula of the compound:
- The concentration of the chloride is 0.1 M.
- The formula of the compound contains one chloride ion (Cl-).
- Therefore, the formula of the compound is XCl2, where X is the symbol of the element other than chlorine.
Hence, the correct answer is option 'C' XCl2.
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Community Answer
In an experiment it showed that 10 mL of 0.05 M solution of chloride r...
Agno3 takes one cl aton per molecule
so y*10*0.05=10*0.1
y= 2
so 2 cl aton
now B option is incorrect bcz it have write xcl instead of x2cl2
so y*10*0.05=10*0.1
y= 2
so 2 cl aton
now B option is incorrect bcz it have write xcl instead of x2cl2
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In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine): [NEET Kar. 2013]a)X2Clb)X2Cl2c)XCl2d)XCl4Correct answer is option 'C'. Can you explain this answer?
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In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine): [NEET Kar. 2013]a)X2Clb)X2Cl2c)XCl2d)XCl4Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine): [NEET Kar. 2013]a)X2Clb)X2Cl2c)XCl2d)XCl4Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine): [NEET Kar. 2013]a)X2Clb)X2Cl2c)XCl2d)XCl4Correct answer is option 'C'. Can you explain this answer?.
In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine): [NEET Kar. 2013]a)X2Clb)X2Cl2c)XCl2d)XCl4Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine): [NEET Kar. 2013]a)X2Clb)X2Cl2c)XCl2d)XCl4Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine): [NEET Kar. 2013]a)X2Clb)X2Cl2c)XCl2d)XCl4Correct answer is option 'C'. Can you explain this answer?.
Solutions for In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine): [NEET Kar. 2013]a)X2Clb)X2Cl2c)XCl2d)XCl4Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine): [NEET Kar. 2013]a)X2Clb)X2Cl2c)XCl2d)XCl4Correct answer is option 'C'. Can you explain this answer?, a detailed solution for In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine): [NEET Kar. 2013]a)X2Clb)X2Cl2c)XCl2d)XCl4Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine): [NEET Kar. 2013]a)X2Clb)X2Cl2c)XCl2d)XCl4Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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