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Haemoglobin contains 0.334% of iron by weight.The molecular weight of haemoglobin is approximately 67200. The number of iron atoms (at. wt. of Fe is 56) present in one molecule of haemoglobin are [1998]
  • a)
    1
  • b)
    6
  • c)
    4
  • d)
    2
Correct answer is option 'C'. Can you explain this answer?
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Haemoglobin contains 0.334% of iron by weight.The molecular weight of ...
Given : Percentage of the iron = 0.334%; Molecular weight of the haemoglobin = 67200 and atomic weight of the iron = 56. We know that the number of iron atoms
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Haemoglobin contains 0.334% of iron by weight.The molecular weight of ...
Given:
Percentage of iron in haemoglobin by weight = 0.334%
Molecular weight of haemoglobin = 67200
Atomic weight of iron (Fe) = 56

To find: Number of iron atoms present in one molecule of haemoglobin

Solution:
1. Calculate the mass of iron present in one molecule of haemoglobin:
Mass of iron = 0.334% of 67200
= (0.334/100) x 67200
= 224.448 g

2. Calculate the number of moles of iron:
Number of moles = Mass/Molar mass
Molar mass of iron = 56 g/mol
Number of moles of iron = 224.448/56
= 4.001

3. Since there are 4 atoms of iron in 1 mole of iron, the number of iron atoms present in one molecule of haemoglobin is:
4 x 4.001 = 16.004

Rounding off to the nearest whole number, we get: 16 ≈ 4

Therefore, the number of iron atoms present in one molecule of haemoglobin is 4.

Answer: Option (c) 4.
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Haemoglobin contains 0.334% of iron by weight.The molecular weight of haemoglobin is approximately 67200. The number of iron atoms (at. wt. of Fe is 56) present in one molecule of haemoglobin are [1998]a)1b)6c)4d)2Correct answer is option 'C'. Can you explain this answer?
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