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Two sound waves with wavelengths 5.0 m and 5.5m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second [2006]
- a)0
- b)1
- c)6
- d)12
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Two sound waves with wavelengths 5.0 m and 5.5m respectively, each pro...
Frequencies of sound waves are 
i.e., 66 Hz and 60 Hz
Frequencies of beat = 66 – 60 = 6 per second
i.e., 66 Hz and 60 HzFrequencies of beat = 66 – 60 = 6 per second
Most Upvoted Answer
Two sound waves with wavelengths 5.0 m and 5.5m respectively, each pro...
Understanding Sound Waves and Beats
When two sound waves with different frequencies interfere, they produce a phenomenon known as "beats." The number of beats per second (beat frequency) is determined by the difference in their frequencies.
Calculating Frequencies
To find the frequencies of the sound waves, we use the formula:
Frequency (f) = Velocity (v) / Wavelength (λ)
For the two given wavelengths:
- Wave 1 (λ1 = 5.0 m):
- f1 = 330 m/s / 5.0 m = 66 Hz
- Wave 2 (λ2 = 5.5 m):
- f2 = 330 m/s / 5.5 m = 60 Hz
Finding the Beat Frequency
The beat frequency is calculated by taking the absolute difference between the two frequencies:
- Beat Frequency (f_beat) = |f1 - f2| = |66 Hz - 60 Hz| = 6 Hz
This means that the two sound waves will create 6 beats per second.
Conclusion
Thus, the expected number of beats per second when two sound waves with wavelengths of 5.0 m and 5.5 m propagate in a gas at 330 m/s is indeed:
- Correct Answer: Option 'C' - 6 beats per second.
This understanding of sound wave interference is crucial for related topics in physics and can help in various applications, such as musical acoustics and sound engineering.
When two sound waves with different frequencies interfere, they produce a phenomenon known as "beats." The number of beats per second (beat frequency) is determined by the difference in their frequencies.
Calculating Frequencies
To find the frequencies of the sound waves, we use the formula:
Frequency (f) = Velocity (v) / Wavelength (λ)
For the two given wavelengths:
- Wave 1 (λ1 = 5.0 m):
- f1 = 330 m/s / 5.0 m = 66 Hz
- Wave 2 (λ2 = 5.5 m):
- f2 = 330 m/s / 5.5 m = 60 Hz
Finding the Beat Frequency
The beat frequency is calculated by taking the absolute difference between the two frequencies:
- Beat Frequency (f_beat) = |f1 - f2| = |66 Hz - 60 Hz| = 6 Hz
This means that the two sound waves will create 6 beats per second.
Conclusion
Thus, the expected number of beats per second when two sound waves with wavelengths of 5.0 m and 5.5 m propagate in a gas at 330 m/s is indeed:
- Correct Answer: Option 'C' - 6 beats per second.
This understanding of sound wave interference is crucial for related topics in physics and can help in various applications, such as musical acoustics and sound engineering.
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Two sound waves with wavelengths 5.0 m and 5.5m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second [2006]a)0b)1c)6d)12Correct answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two sound waves with wavelengths 5.0 m and 5.5m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second [2006]a)0b)1c)6d)12Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two sound waves with wavelengths 5.0 m and 5.5m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second [2006]a)0b)1c)6d)12Correct answer is option 'C'. Can you explain this answer?.
Two sound waves with wavelengths 5.0 m and 5.5m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second [2006]a)0b)1c)6d)12Correct answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two sound waves with wavelengths 5.0 m and 5.5m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second [2006]a)0b)1c)6d)12Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two sound waves with wavelengths 5.0 m and 5.5m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second [2006]a)0b)1c)6d)12Correct answer is option 'C'. Can you explain this answer?.
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Two sound waves with wavelengths 5.0 m and 5.5m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second [2006]a)0b)1c)6d)12Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Two sound waves with wavelengths 5.0 m and 5.5m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second [2006]a)0b)1c)6d)12Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Two sound waves with wavelengths 5.0 m and 5.5m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second [2006]a)0b)1c)6d)12Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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