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The tangent at the point ‘a’on the ellipse meets the auxiliary circle in two points which subtends a right angle at the centre, then the eccentricity ‘e’ of the ellipse is given by the equation :a)e2 (1 + cos2 α) = 1b)e2 (cosec2α - 1) = 1c)e2 (1 + sin2 α) = 1d)e2 (1 + tan2 α) = 1Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The tangent at the point ‘a’on the ellipse meets the auxiliary circle in two points which subtends a right angle at the centre, then the eccentricity ‘e’ of the ellipse is given by the equation :a)e2 (1 + cos2 α) = 1b)e2 (cosec2α - 1) = 1c)e2 (1 + sin2 α) = 1d)e2 (1 + tan2 α) = 1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The tangent at the point ‘a’on the ellipse meets the auxiliary circle in two points which subtends a right angle at the centre, then the eccentricity ‘e’ of the ellipse is given by the equation :a)e2 (1 + cos2 α) = 1b)e2 (cosec2α - 1) = 1c)e2 (1 + sin2 α) = 1d)e2 (1 + tan2 α) = 1Correct answer is option 'C'. Can you explain this answer?.

Solutions for The tangent at the point ‘a’on the ellipse meets the auxiliary circle in two points which subtends a right angle at the centre, then the eccentricity ‘e’ of the ellipse is given by the equation :a)e2 (1 + cos2 α) = 1b)e2 (cosec2α - 1) = 1c)e2 (1 + sin2 α) = 1d)e2 (1 + tan2 α) = 1Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The tangent at the point ‘a’on the ellipse meets the auxiliary circle in two points which subtends a right angle at the centre, then the eccentricity ‘e’ of the ellipse is given by the equation :a)e2 (1 + cos2 α) = 1b)e2 (cosec2α - 1) = 1c)e2 (1 + sin2 α) = 1d)e2 (1 + tan2 α) = 1Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The tangent at the point ‘a’on the ellipse meets the auxiliary circle in two points which subtends a right angle at the centre, then the eccentricity ‘e’ of the ellipse is given by the equation :a)e2 (1 + cos2 α) = 1b)e2 (cosec2α - 1) = 1c)e2 (1 + sin2 α) = 1d)e2 (1 + tan2 α) = 1Correct answer is option 'C'. Can you explain this answer?, a detailed solution for The tangent at the point ‘a’on the ellipse meets the auxiliary circle in two points which subtends a right angle at the centre, then the eccentricity ‘e’ of the ellipse is given by the equation :a)e2 (1 + cos2 α) = 1b)e2 (cosec2α - 1) = 1c)e2 (1 + sin2 α) = 1d)e2 (1 + tan2 α) = 1Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of The tangent at the point ‘a’on the ellipse meets the auxiliary circle in two points which subtends a right angle at the centre, then the eccentricity ‘e’ of the ellipse is given by the equation :a)e2 (1 + cos2 α) = 1b)e2 (cosec2α - 1) = 1c)e2 (1 + sin2 α) = 1d)e2 (1 + tan2 α) = 1Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The tangent at the point ‘a’on the ellipse meets the auxiliary circle in two points which subtends a right angle at the centre, then the eccentricity ‘e’ of the ellipse is given by the equation :a)e2 (1 + cos2 α) = 1b)e2 (cosec2α - 1) = 1c)e2 (1 + sin2 α) = 1d)e2 (1 + tan2 α) = 1Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.