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Divide the given polynomial by the given monominal: 8 (x3y2z2 + x2y3z2 + x2y2z3) ÷ 4x2y2z2
- a)(x + y + z)
- b)2(x + y + z)
- c)2
- d)none of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Divide the given polynomial by the given monominal: 8 (x3y2z2 + x2y3z2...
8 (x3y2z2 + x2y3z2 + x2y2z3) ÷ 4x2y2z2
= 
Most Upvoted Answer
Divide the given polynomial by the given monominal: 8 (x3y2z2 + x2y3z2...
To divide a polynomial by a monomial, we need to divide each term in the polynomial by the monomial.
Given polynomial: 8x^3y^2z^2 - x^2y^3z^2 - x^2y^2z^3
Given monomial: 8
Dividing each term by the monomial 8:
(8x^3y^2z^2)/8 = x^3y^2z^2
(-x^2y^3z^2)/8 = -1/8 * x^2y^3z^2
(-x^2y^2z^3)/8 = -1/8 * x^2y^2z^3
Therefore, the result of dividing the given polynomial by the monomial 8 is:
x^3y^2z^2 - (1/8)x^2y^3z^2 - (1/8)x^2y^2z^3
Given polynomial: 8x^3y^2z^2 - x^2y^3z^2 - x^2y^2z^3
Given monomial: 8
Dividing each term by the monomial 8:
(8x^3y^2z^2)/8 = x^3y^2z^2
(-x^2y^3z^2)/8 = -1/8 * x^2y^3z^2
(-x^2y^2z^3)/8 = -1/8 * x^2y^2z^3
Therefore, the result of dividing the given polynomial by the monomial 8 is:
x^3y^2z^2 - (1/8)x^2y^3z^2 - (1/8)x^2y^2z^3
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