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The rate of reaction between two reactants A and B decreases by a factor of 4 if the concentration of reactant B is doubled. The order of this reaction with respect to reactant B is:[2005]
- a)2
- b)-2
- c)1
- d)-1
Correct answer is option 'B'. Can you explain this answer?
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Understanding the Reaction Rate
The rate of a chemical reaction can be expressed using the rate law, which is determined by the concentrations of the reactants and their respective orders. For a reaction involving reactants A and B, the rate can be represented as:
Rate = k [A]^m [B]^n
Where:
- k = rate constant
- [A] = concentration of reactant A
- [B] = concentration of reactant B
- m = order with respect to A
- n = order with respect to B
Effect of Doubling Concentration
According to the problem, when the concentration of B is doubled, the rate of reaction decreases by a factor of 4. This means:
New Rate = Rate / 4 when [B] is changed to 2[B]
Mathematical Representation
Let’s set the original rate when [B] is at its original concentration:
Original Rate = k [A]^m [B]^n
When the concentration of B is doubled, the new rate will be:
New Rate = k [A]^m (2[B])^n = k [A]^m (2^n [B]^n) = 2^n * k [A]^m [B]^n
Setting these equal according to the problem:
2^n * (Original Rate) = (Original Rate) / 4
Solving for n
Cancelling the original rate from both sides, we get:
2^n = 1/4
This can be rewritten as:
2^n = 2^(-2)
Thus, n = -2.
Conclusion
The order of the reaction with respect to reactant B is -2, indicating that increasing the concentration of B leads to a significant decrease in the reaction rate. Hence, the correct answer is option 'b) -2'.
The rate of a chemical reaction can be expressed using the rate law, which is determined by the concentrations of the reactants and their respective orders. For a reaction involving reactants A and B, the rate can be represented as:
Rate = k [A]^m [B]^n
Where:
- k = rate constant
- [A] = concentration of reactant A
- [B] = concentration of reactant B
- m = order with respect to A
- n = order with respect to B
Effect of Doubling Concentration
According to the problem, when the concentration of B is doubled, the rate of reaction decreases by a factor of 4. This means:
New Rate = Rate / 4 when [B] is changed to 2[B]
Mathematical Representation
Let’s set the original rate when [B] is at its original concentration:
Original Rate = k [A]^m [B]^n
When the concentration of B is doubled, the new rate will be:
New Rate = k [A]^m (2[B])^n = k [A]^m (2^n [B]^n) = 2^n * k [A]^m [B]^n
Setting these equal according to the problem:
2^n * (Original Rate) = (Original Rate) / 4
Solving for n
Cancelling the original rate from both sides, we get:
2^n = 1/4
This can be rewritten as:
2^n = 2^(-2)
Thus, n = -2.
Conclusion
The order of the reaction with respect to reactant B is -2, indicating that increasing the concentration of B leads to a significant decrease in the reaction rate. Hence, the correct answer is option 'b) -2'.
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The rate of reaction between two reactants A and B decreases by a factor of 4 if the concentration of reactant B is doubled. The order of this reaction with respect to reactant B is:[2005]a)2b)-2c)1d)-1Correct answer is option 'B'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The rate of reaction between two reactants A and B decreases by a factor of 4 if the concentration of reactant B is doubled. The order of this reaction with respect to reactant B is:[2005]a)2b)-2c)1d)-1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The rate of reaction between two reactants A and B decreases by a factor of 4 if the concentration of reactant B is doubled. The order of this reaction with respect to reactant B is:[2005]a)2b)-2c)1d)-1Correct answer is option 'B'. Can you explain this answer?.
The rate of reaction between two reactants A and B decreases by a factor of 4 if the concentration of reactant B is doubled. The order of this reaction with respect to reactant B is:[2005]a)2b)-2c)1d)-1Correct answer is option 'B'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The rate of reaction between two reactants A and B decreases by a factor of 4 if the concentration of reactant B is doubled. The order of this reaction with respect to reactant B is:[2005]a)2b)-2c)1d)-1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The rate of reaction between two reactants A and B decreases by a factor of 4 if the concentration of reactant B is doubled. The order of this reaction with respect to reactant B is:[2005]a)2b)-2c)1d)-1Correct answer is option 'B'. Can you explain this answer?.
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