Two electric charges of 9 microcoulomb and minus 3 microcoulomb are placed 0.16 metre apart in a there will be a point P at which electric potential is zero on the line joining of two charges and in between them the distance of P from 9 microcoulomb charge is?

Question

Answer

Problem Statement: Two electric charges of 9 microcoulomb and minus 3 microcoulomb are placed 0.16 metre apart in a there will be a point P at which electric potential is zero on the line joining of two charges and in between them the distance of P from 9 microcoulomb charge is? Explain in details.

Explanation:

In order to find the distance of point P from the 9 microcoulomb charge, we need to follow the steps given below:

Calculate the electric field at point P due to both the charges.

Use the formula for electric potential to calculate the potential at point P due to both the charges.

Set the potential at point P to zero and solve for the distance of point P from the 9 microcoulomb charge.

Calculation:

The formula for electric field at a point due to a point charge is given by:

E = k*q/r^2

where:

E is the electric field

k is the Coulomb constant (9 x 10^9 Nm^2/C^2)

q is the charge

r is the distance between the point charge and the point where electric field is to be calculated

Using the above formula, we can calculate the electric field at point P due to both the charges:

Electric field due to 9 microcoulomb charge:

E1 = k*q1/r1^2 = (9 x 10^9)*(9 x 10^-6)/(r1)^2

Electric field due to -3 microcoulomb charge:

E2 = k*q2/r2^2 = (9 x 10^9)*(-3 x 10^-6)/(0.16 - r2)^2

The total electric field at point P is given by:

E = E1 + E2

The formula for electric potential at a point due to a point charge is given by:

V = k*q/r

Using the above formula, we can calculate the potential at point P due to both the charges:

Potential due to 9 microcoulomb charge:

V1 = k*q1/r1 = (9 x 10^9)*(9 x 10^-6)/r1

Potential due to -3 microcoulomb charge:

V2 = k*q2/r2 = (9 x 10^9)*(-3 x 10^-6)/(0.16 - r2)

The total potential at point P is given by:

V = V1 + V2

Setting the potential at point P to zero, we get:

V1 + V2 = 0

Answer

Similar Class 12 Doubts

Two electric charges of 9 microcoulomb and minus 3 microcoulomb are placed 0.16 metre apart in a there will be a point P at which electric potential is zero on the line joining the tour charges in between them the distance of P from 9 microcoulomb charges is?

A charge of 20 unit is placed at a distance 50cm from the another charge 80 unit. At what point on the line joining the two charges will the field and potential be zero?

Two charges 5×10(-8)and 3×10^(-8) are located 16 cm apart. at what points on the line joining the two charges is the electric potential zero?Take the potential at infinity to be zero?

Two point charge 0.01microcoulomb and -0.01 microcoulomb are placed apart in vacuum. Calculate the magnitude of electric field intensity at the middle point of the line joining the chargs and mention its direction.?

Top Courses for Class 12

Suggested Free Tests

Related Content

Schools

Competitive Examinations

Quick Access Links

Technical Exams