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A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,
  • a)
    the magnitude of the electric field remains the same.
  • b)
    the direction of the electric field remains the same.
  • c)
    the electric potential increases continuously.
  • d)
    the electric poten tial increases at first, then decreases and again increases.
Correct answer is option 'B,C'. Can you explain this answer?
Most Upvoted Answer
A dielectric slab of thickness d is inserted in a parallel plate capac...
In region I and III, there will be electric field   directedfrom positive to negative. In region II, due to orientation of dipoles, there is an electric field  present in opposite
direction of   But since  is also present, the net electric field is  in the direction of    as shown in the diagram. (∵ E0 > Ek)

NOTE : When one moves opposite to the direction of electric field, the potential always increases. The stronger the electric field, the more is the potential increase. Since in region II, the electric field is less as compared to I and III therefore the increase in potential will be less but there has to be increase in potential in all the regions from x = 0 to x = 3d. Also where
E is uniform, dV/dx = constt.
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Community Answer
A dielectric slab of thickness d is inserted in a parallel plate capac...
Electric Field:
- The magnitude of the electric field remains the same as the dielectric slab does not alter the charge distribution on the plates. The electric field is determined by the charge on the plates and their separation distance, which remains constant in this scenario.

Electric Potential:
- The electric potential increases continuously as we move from the negative plate (x = 0) to the positive plate (x = 3d). This is because the electric potential is the work done in moving a unit positive charge from one point to another in an electric field. Since the electric field is constant and points from the positive plate to the negative plate, the potential increases continuously.
Therefore, the correct answers are option 'B, C'.
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A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer?
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A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer?.
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