JEE Exam > JEE Questions > A dielectric slab of thickness d is inserted ...
Start Learning for Free
A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,
- a)the magnitude of the electric field remains the same.
- b)the direction of the electric field remains the same.
- c)the electric potential increases continuously.
- d)the electric poten tial increases at first, then decreases and again increases.
Correct answer is option 'B,C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A dielectric slab of thickness d is inserted in a parallel plate capac...
In region I and III, there will be electric field 
directedfrom positive to negative. In region II, due to orientation of dipoles, there is an electric field 
present in opposite
direction of But since is also present, the net electric field is 
in the direction of as shown in the diagram. (∵ E0 > Ek)
directedfrom positive to negative. In region II, due to orientation of dipoles, there is an electric field present in oppositedirection of
But since is also present, the net electric field is in the direction of as shown in the diagram. (∵ E0 > Ek)
NOTE : When one moves opposite to the direction of electric field, the potential always increases. The stronger the electric field, the more is the potential increase. Since in region II, the electric field is less as compared to I and III therefore the increase in potential will be less but there has to be increase in potential in all the regions from x = 0 to x = 3d. Also where
E is uniform, dV/dx = constt.
Free Test
| FREE | Start Free Test |
Community Answer
A dielectric slab of thickness d is inserted in a parallel plate capac...
Electric Field:
- The magnitude of the electric field remains the same as the dielectric slab does not alter the charge distribution on the plates. The electric field is determined by the charge on the plates and their separation distance, which remains constant in this scenario.
Electric Potential:
- The electric potential increases continuously as we move from the negative plate (x = 0) to the positive plate (x = 3d). This is because the electric potential is the work done in moving a unit positive charge from one point to another in an electric field. Since the electric field is constant and points from the positive plate to the negative plate, the potential increases continuously.
Therefore, the correct answers are option 'B, C'.
- The magnitude of the electric field remains the same as the dielectric slab does not alter the charge distribution on the plates. The electric field is determined by the charge on the plates and their separation distance, which remains constant in this scenario.
Electric Potential:
- The electric potential increases continuously as we move from the negative plate (x = 0) to the positive plate (x = 3d). This is because the electric potential is the work done in moving a unit positive charge from one point to another in an electric field. Since the electric field is constant and points from the positive plate to the negative plate, the potential increases continuously.
Therefore, the correct answers are option 'B, C'.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer?
Question Description
A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer?.
A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer?.
Solutions for A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer?, a detailed solution for A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer? has been provided alongside types of A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x = 0 and positive plate is at x = 3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d,a)the magnitude of the electric field remains the same.b)the direction of the electric field remains the same.c)the electric potential increases continuously.d)the electric poten tial increases at first, then decreases and again increases.Correct answer is option 'B,C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup