Class 12 Exam > Class 12 Questions > The standard e.m.f. of a galvanic cell involv...
Start Learning for Free
The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25°C. The equilibrium constant of the reaction would be (Given F = 96500 C mol–1; R = 8.314JK– 1mol–1)[2004]
- a)2.0 x 1011
- b)4.0 x 1012
- c)1.0 x 102
- d)1.0 x 1010
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The standard e.m.f. of a galvanic cell involving cell reaction with n ...
Here, n = 2, E° = 0.295
Most Upvoted Answer
The standard e.m.f. of a galvanic cell involving cell reaction with n ...
°C. Calculate the equilibrium constant (K) for the cell reaction.
The cell reaction can be represented as:
aA + bB → cC + dD
where a = c = 1 and b = d = 2 (since n = 2).
The Nernst equation relates the standard emf of the cell (E°cell) to the equilibrium constant (K) and the activities of the reactants and products:
Ecell = E°cell - (RT/nF) ln K
where R is the gas constant, T is the temperature in kelvin, F is the Faraday constant, and ln is the natural logarithm.
At 25°C, the value of R is 8.314 J/(mol·K) and the value of F is 96,485 C/mol.
Substituting the given values:
0.295 V = E°cell - (8.314 J/(mol·K) × 298 K / (2 × 96,485 C/mol)) ln K
0.295 V = E°cell - 0.0591 V ln K
ln K = (E°cell - 0.295 V) / 0.0591 V
ln K = (0.0 V - 0.295 V) / 0.0591 V
ln K = -4.98
K = e^-4.98
K = 1.07 × 10^-2
Therefore, the equilibrium constant for the cell reaction is 1.07 × 10^-2.
The cell reaction can be represented as:
aA + bB → cC + dD
where a = c = 1 and b = d = 2 (since n = 2).
The Nernst equation relates the standard emf of the cell (E°cell) to the equilibrium constant (K) and the activities of the reactants and products:
Ecell = E°cell - (RT/nF) ln K
where R is the gas constant, T is the temperature in kelvin, F is the Faraday constant, and ln is the natural logarithm.
At 25°C, the value of R is 8.314 J/(mol·K) and the value of F is 96,485 C/mol.
Substituting the given values:
0.295 V = E°cell - (8.314 J/(mol·K) × 298 K / (2 × 96,485 C/mol)) ln K
0.295 V = E°cell - 0.0591 V ln K
ln K = (E°cell - 0.295 V) / 0.0591 V
ln K = (0.0 V - 0.295 V) / 0.0591 V
ln K = -4.98
K = e^-4.98
K = 1.07 × 10^-2
Therefore, the equilibrium constant for the cell reaction is 1.07 × 10^-2.
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25°C. The equilibrium constant of the reaction would be (Given F = 96500 C mol–1; R = 8.314JK– 1mol–1)[2004]a)2.0 x 1011b)4.0 x 1012c)1.0 x 102d)1.0 x 1010Correct answer is option 'D'. Can you explain this answer?
Question Description
The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25°C. The equilibrium constant of the reaction would be (Given F = 96500 C mol–1; R = 8.314JK– 1mol–1)[2004]a)2.0 x 1011b)4.0 x 1012c)1.0 x 102d)1.0 x 1010Correct answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25°C. The equilibrium constant of the reaction would be (Given F = 96500 C mol–1; R = 8.314JK– 1mol–1)[2004]a)2.0 x 1011b)4.0 x 1012c)1.0 x 102d)1.0 x 1010Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25°C. The equilibrium constant of the reaction would be (Given F = 96500 C mol–1; R = 8.314JK– 1mol–1)[2004]a)2.0 x 1011b)4.0 x 1012c)1.0 x 102d)1.0 x 1010Correct answer is option 'D'. Can you explain this answer?.
The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25°C. The equilibrium constant of the reaction would be (Given F = 96500 C mol–1; R = 8.314JK– 1mol–1)[2004]a)2.0 x 1011b)4.0 x 1012c)1.0 x 102d)1.0 x 1010Correct answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25°C. The equilibrium constant of the reaction would be (Given F = 96500 C mol–1; R = 8.314JK– 1mol–1)[2004]a)2.0 x 1011b)4.0 x 1012c)1.0 x 102d)1.0 x 1010Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25°C. The equilibrium constant of the reaction would be (Given F = 96500 C mol–1; R = 8.314JK– 1mol–1)[2004]a)2.0 x 1011b)4.0 x 1012c)1.0 x 102d)1.0 x 1010Correct answer is option 'D'. Can you explain this answer?.
Solutions for The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25°C. The equilibrium constant of the reaction would be (Given F = 96500 C mol–1; R = 8.314JK– 1mol–1)[2004]a)2.0 x 1011b)4.0 x 1012c)1.0 x 102d)1.0 x 1010Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25°C. The equilibrium constant of the reaction would be (Given F = 96500 C mol–1; R = 8.314JK– 1mol–1)[2004]a)2.0 x 1011b)4.0 x 1012c)1.0 x 102d)1.0 x 1010Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25°C. The equilibrium constant of the reaction would be (Given F = 96500 C mol–1; R = 8.314JK– 1mol–1)[2004]a)2.0 x 1011b)4.0 x 1012c)1.0 x 102d)1.0 x 1010Correct answer is option 'D'. Can you explain this answer?, a detailed solution for The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25°C. The equilibrium constant of the reaction would be (Given F = 96500 C mol–1; R = 8.314JK– 1mol–1)[2004]a)2.0 x 1011b)4.0 x 1012c)1.0 x 102d)1.0 x 1010Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25°C. The equilibrium constant of the reaction would be (Given F = 96500 C mol–1; R = 8.314JK– 1mol–1)[2004]a)2.0 x 1011b)4.0 x 1012c)1.0 x 102d)1.0 x 1010Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The standard e.m.f. of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 25°C. The equilibrium constant of the reaction would be (Given F = 96500 C mol–1; R = 8.314JK– 1mol–1)[2004]a)2.0 x 1011b)4.0 x 1012c)1.0 x 102d)1.0 x 1010Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup