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In a common emitter (CE) amplifier having a voltage gain G, the transistor used has transconductance 0.03 mho and current gain 25. If the above transistor is replaced with another one with transconductance 0.02 mho and current gain 20, the voltage gain will be   [NEET 2013] 
  • a)
    1.5 G
  • b)
    1/3 G
  • c)
    5/4 G
  • d)
    2/3 G
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
In a common emitter (CE) amplifier having a voltage gain G, the transi...
Given:
Transconductance of 1st transistor (gm1) = 0.03 mho
Current gain of 1st transistor (β1) = 25
Voltage gain of Common Emitter amplifier = G

To Find:
Voltage gain of Common Emitter amplifier when the transistor is replaced with another one with gm2 = 0.02 mho and β2 = 20

Solution:
We know that the voltage gain of a common emitter amplifier is given by the formula:
G = -gm * R_c * β

Where gm is the transconductance of the transistor, Rc is the collector resistance and β is the current gain.

Let's assume that the collector resistance remains the same in both cases. Therefore, we can write:

G1 = -gm1 * Rc * β1
G2 = -gm2 * Rc * β2

Dividing G2 by G1, we get:

G2/G1 = (-gm2 * Rc * β2) / (-gm1 * Rc * β1)

Simplifying the above equation, we get:

G2/G1 = (gm1/gm2) * (β2/β1)

Substituting the given values, we get:

G2/G1 = (0.03/0.02) * (20/25) = 0.9

Therefore, the voltage gain of the common emitter amplifier when the transistor is replaced with another one with gm2 = 0.02 mho and β2 = 20 is:

G2 = G1 * (G2/G1) = G * 0.9

G2 = 0.9G

Hence, the correct option is (d) 2/3 G.
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In a common emitter (CE) amplifier having a voltage gain G, the transi...
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In a common emitter (CE) amplifier having a voltage gain G, the transistor used has transconductance 0.03 mho and current gain 25. If the above transistor is replaced with another one with transconductance 0.02 mho and current gain 20, the voltage gain will be [NEET 2013]a)1.5 Gb)1/3 Gc)5/4 Gd)2/3 GCorrect answer is option 'D'. Can you explain this answer?
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