In an arrangement shown in figure pulleys are massless and frictionles...
The arrangement consists of two pulleys, two blocks, and a thread connecting them. The pulleys are assumed to be massless and frictionless, and the thread is light and inextensible. The question asks under what conditions the block of mass M1 will remain at rest.
1. Analysis of Forces:
To determine the conditions for the block of mass M1 to remain at rest, we need to analyze the forces acting on it. There are two main forces to consider:
- Tension in the thread: The tension in the thread will exert a force on the block of mass M1. This force can be directed upwards or downwards depending on the arrangement of the pulleys and the masses of the blocks.
- Weight of the block: The block of mass M1 will experience a downward force due to its weight, which is given by the equation F = m1 * g, where m1 is the mass of the block and g is the acceleration due to gravity.
2. Possible Scenarios:
There are two possible scenarios that will allow the block of mass M1 to remain at rest:
- Equal masses: If the masses of the two blocks are equal, i.e., M1 = M2, and the pulleys are arranged in such a way that the tension in the thread is equal to the weight of the block, then the block of mass M1 will remain at rest. In this case, the tension in the thread will balance the weight of the block, resulting in no net force acting on it.
- Equal acceleration: If the masses of the blocks are different, i.e., M1 ≠ M2, and the pulleys are arranged in such a way that the acceleration of the system is zero, then the block of mass M1 will also remain at rest. In this case, the tension in the thread will be different from the weight of the block, but the net force on the block will be zero because the acceleration is zero.
3. Conclusion:
In conclusion, the block of mass M1 will remain at rest if either the masses of the blocks are equal and the tension in the thread is equal to the weight of the block or if the masses of the blocks are different and the acceleration of the system is zero. These conditions ensure that the net force acting on the block of mass M1 is zero, resulting in its equilibrium.
In an arrangement shown in figure pulleys are massless and frictionles...
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