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The perimeter of isosceles triangle is equal to the 14 centimetre the lateral side is to the base in the ratio 5: 4 the area of the triangle is?
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The perimeter of isosceles triangle is equal to the 14 centimetre the ...
Let lateral side = (5x)cm and base = (4x) cm
5x+5x+4x=14 or x = 1
So, the sides are 5 cm, 5 cm and 4 cm
Semi perimeter, S = 1/2(5+5+4)cm = 7cm.
(s-a)=2cm, (s-b)=2cm and (s-c)=3cm
Area of triangle
= √(s(s-a)(s-b)(s-c))
= √(7x2x2x3)
= 2√21
This question is part of UPSC exam. View all Class 9 courses
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The perimeter of isosceles triangle is equal to the 14 centimetre the ...
Perimeter and Ratio of Sides:
Given that the perimeter of the isosceles triangle is 14 cm and the ratio of the lateral side to the base is 5:4.
Calculating Side Lengths:
Let the base of the triangle be 4x and each of the lateral sides be 5x.
Therefore, the perimeter = 4x + 5x + 5x = 14 cm
=> 14x = 14
=> x = 1
Therefore, the base of the triangle = 4(1) = 4 cm
And each lateral side = 5(1) = 5 cm
Finding the Height:
Let h be the height of the triangle. Using Pythagorean theorem, we can find the height.
h^2 + (2.5)^2 = 5^2
h^2 + 6.25 = 25
h^2 = 18.75
h = √18.75 ≈ 4.33 cm
Calculating Area:
The area of the triangle can be calculated using the formula: Area = 0.5 * base * height
=> Area = 0.5 * 4 * 4.33
=> Area = 8.66 sq cm
Therefore, the area of the isosceles triangle is approximately 8.66 square centimeters.
Given that the perimeter of the isosceles triangle is 14 cm and the ratio of the lateral side to the base is 5:4.
Calculating Side Lengths:
Let the base of the triangle be 4x and each of the lateral sides be 5x.
Therefore, the perimeter = 4x + 5x + 5x = 14 cm
=> 14x = 14
=> x = 1
Therefore, the base of the triangle = 4(1) = 4 cm
And each lateral side = 5(1) = 5 cm
Finding the Height:
Let h be the height of the triangle. Using Pythagorean theorem, we can find the height.
h^2 + (2.5)^2 = 5^2
h^2 + 6.25 = 25
h^2 = 18.75
h = √18.75 ≈ 4.33 cm
Calculating Area:
The area of the triangle can be calculated using the formula: Area = 0.5 * base * height
=> Area = 0.5 * 4 * 4.33
=> Area = 8.66 sq cm
Therefore, the area of the isosceles triangle is approximately 8.66 square centimeters.
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The perimeter of isosceles triangle is equal to the 14 centimetre the lateral side is to the base in the ratio 5: 4 the area of the triangle is?
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The perimeter of isosceles triangle is equal to the 14 centimetre the lateral side is to the base in the ratio 5: 4 the area of the triangle is? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about The perimeter of isosceles triangle is equal to the 14 centimetre the lateral side is to the base in the ratio 5: 4 the area of the triangle is? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The perimeter of isosceles triangle is equal to the 14 centimetre the lateral side is to the base in the ratio 5: 4 the area of the triangle is?.
The perimeter of isosceles triangle is equal to the 14 centimetre the lateral side is to the base in the ratio 5: 4 the area of the triangle is? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about The perimeter of isosceles triangle is equal to the 14 centimetre the lateral side is to the base in the ratio 5: 4 the area of the triangle is? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The perimeter of isosceles triangle is equal to the 14 centimetre the lateral side is to the base in the ratio 5: 4 the area of the triangle is?.
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