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Three rods of Copper, Brass and Steel are welded together to form a Y shaped structure. Area of cross - section of each rod = 4cm 2 . End of copper rod is maintained at 100°C where as ends of brass and steel are kept at 0°C. Lengths of the copper,, brass and steel rods are 46, 13 and 12 cms respectively. The rods are thermally insulated from surroundings excepts at ends. Thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.12 CGS units respectively. Rate of heat flow through copper rod is:
- a)1.2 cal/s
- b)2.4 cal/s
- c)4.8 cal/s
- d)6.0 cal/s
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Three rods of Copper, Brass and Steel are welded together to form a Y ...
Rate of heat flow is given by,
Where, K = coefficient of thermal conductivity l = length of rod and A = Area of cross-section of rod
If the junction temperature is T, then
Most Upvoted Answer
Three rods of Copper, Brass and Steel are welded together to form a Y ...
Area of cross section A =4cm2=4×10−2m−2
tA=100∘c
tB=0∘c;tC=0∘c
lcu=46cm;lB=13cm;lS=12cm;
Kcu=0.92,KB=0.26;KS=0.12
the temperature at the junction point be 't'
Hcu=HB+HS
⟹KcuA(tA−t)lcu=KB(t−tB)lB+KS(t−tS)lS
⟹0.92(100−t)46=0.26(t−0)13+0..12(t−0)12
On solving we get
t=40∘c
Hcu=KcuA(100−40)lcu=0.92×4×6046=4.80cal/s
∴ Rate of heat flow through copper rod is 4.80 cal/s
tA=100∘c
tB=0∘c;tC=0∘c
lcu=46cm;lB=13cm;lS=12cm;
Kcu=0.92,KB=0.26;KS=0.12
the temperature at the junction point be 't'
Hcu=HB+HS
⟹KcuA(tA−t)lcu=KB(t−tB)lB+KS(t−tS)lS
⟹0.92(100−t)46=0.26(t−0)13+0..12(t−0)12
On solving we get
t=40∘c
Hcu=KcuA(100−40)lcu=0.92×4×6046=4.80cal/s
∴ Rate of heat flow through copper rod is 4.80 cal/s
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Three rods of Copper, Brass and Steel are welded together to form a Y ...
°C while the ends of the brass and steel rods are maintained at 0°C. The rods are 50 cm long and the thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.13 CGS units respectively. Find the temperature of the junction of the rods.
To solve this problem, we can use the principle of heat conduction. According to this principle, the rate of heat transfer through a material is directly proportional to the temperature difference across it and inversely proportional to its thermal conductivity and cross-sectional area.
Let's denote the temperature of the junction as T. The heat flow through each rod can be calculated using the formula:
Q = (k * A * (T1 - T2)) / L
Where Q is the heat flow, k is the thermal conductivity, A is the cross-sectional area, T1 is the temperature at one end, T2 is the temperature at the other end, and L is the length of the rod.
For the copper rod:
Qcopper = (0.92 * 4 * (100 - T)) / 50
For the brass rod:
Qbrass = (0.26 * 4 * (0 - T)) / 50
For the steel rod:
Qsteel = (0.13 * 4 * (0 - T)) / 50
Since the heat flow through the rods is continuous, the total heat flow should be zero. Therefore,
Qcopper + Qbrass + Qsteel = 0
Substituting the values, we get:
(0.92 * 4 * (100 - T)) / 50 + (0.26 * 4 * (0 - T)) / 50 + (0.13 * 4 * (0 - T)) / 50 = 0
Simplifying the equation:
(3.68 * (100 - T) + 1.04 * (0 - T) + 0.52 * (0 - T)) / 50 = 0
(3.68 * 100 - 3.68T - 1.04T - 0.52T) / 50 = 0
(368 - 5.24T) / 50 = 0
368 - 5.24T = 0
-5.24T = -368
T = -368 / -5.24
T = 70.15
Therefore, the temperature of the junction of the rods is approximately 70.15°C.
To solve this problem, we can use the principle of heat conduction. According to this principle, the rate of heat transfer through a material is directly proportional to the temperature difference across it and inversely proportional to its thermal conductivity and cross-sectional area.
Let's denote the temperature of the junction as T. The heat flow through each rod can be calculated using the formula:
Q = (k * A * (T1 - T2)) / L
Where Q is the heat flow, k is the thermal conductivity, A is the cross-sectional area, T1 is the temperature at one end, T2 is the temperature at the other end, and L is the length of the rod.
For the copper rod:
Qcopper = (0.92 * 4 * (100 - T)) / 50
For the brass rod:
Qbrass = (0.26 * 4 * (0 - T)) / 50
For the steel rod:
Qsteel = (0.13 * 4 * (0 - T)) / 50
Since the heat flow through the rods is continuous, the total heat flow should be zero. Therefore,
Qcopper + Qbrass + Qsteel = 0
Substituting the values, we get:
(0.92 * 4 * (100 - T)) / 50 + (0.26 * 4 * (0 - T)) / 50 + (0.13 * 4 * (0 - T)) / 50 = 0
Simplifying the equation:
(3.68 * (100 - T) + 1.04 * (0 - T) + 0.52 * (0 - T)) / 50 = 0
(3.68 * 100 - 3.68T - 1.04T - 0.52T) / 50 = 0
(368 - 5.24T) / 50 = 0
368 - 5.24T = 0
-5.24T = -368
T = -368 / -5.24
T = 70.15
Therefore, the temperature of the junction of the rods is approximately 70.15°C.
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Three rods of Copper, Brass and Steel are welded together to form a Y shaped structure. Area of cross - section of each rod = 4cm 2 . End of copper rod is maintained at 100°C where as ends of brass and steel are kept at 0°C. Lengths of the copper,, brass and steel rods are 46, 13 and 12 cms respectively. The rods are thermally insulated from surroundings excepts at ends. Thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.12 CGS units respectively. Rate of heat flow through copper rod is:a)1.2 cal/sb)2.4 cal/sc)4.8 cal/sd)6.0 cal/sCorrect answer is option 'C'. Can you explain this answer?
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Three rods of Copper, Brass and Steel are welded together to form a Y shaped structure. Area of cross - section of each rod = 4cm 2 . End of copper rod is maintained at 100°C where as ends of brass and steel are kept at 0°C. Lengths of the copper,, brass and steel rods are 46, 13 and 12 cms respectively. The rods are thermally insulated from surroundings excepts at ends. Thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.12 CGS units respectively. Rate of heat flow through copper rod is:a)1.2 cal/sb)2.4 cal/sc)4.8 cal/sd)6.0 cal/sCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Three rods of Copper, Brass and Steel are welded together to form a Y shaped structure. Area of cross - section of each rod = 4cm 2 . End of copper rod is maintained at 100°C where as ends of brass and steel are kept at 0°C. Lengths of the copper,, brass and steel rods are 46, 13 and 12 cms respectively. The rods are thermally insulated from surroundings excepts at ends. Thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.12 CGS units respectively. Rate of heat flow through copper rod is:a)1.2 cal/sb)2.4 cal/sc)4.8 cal/sd)6.0 cal/sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Three rods of Copper, Brass and Steel are welded together to form a Y shaped structure. Area of cross - section of each rod = 4cm 2 . End of copper rod is maintained at 100°C where as ends of brass and steel are kept at 0°C. Lengths of the copper,, brass and steel rods are 46, 13 and 12 cms respectively. The rods are thermally insulated from surroundings excepts at ends. Thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.12 CGS units respectively. Rate of heat flow through copper rod is:a)1.2 cal/sb)2.4 cal/sc)4.8 cal/sd)6.0 cal/sCorrect answer is option 'C'. Can you explain this answer?.
Three rods of Copper, Brass and Steel are welded together to form a Y shaped structure. Area of cross - section of each rod = 4cm 2 . End of copper rod is maintained at 100°C where as ends of brass and steel are kept at 0°C. Lengths of the copper,, brass and steel rods are 46, 13 and 12 cms respectively. The rods are thermally insulated from surroundings excepts at ends. Thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.12 CGS units respectively. Rate of heat flow through copper rod is:a)1.2 cal/sb)2.4 cal/sc)4.8 cal/sd)6.0 cal/sCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Three rods of Copper, Brass and Steel are welded together to form a Y shaped structure. Area of cross - section of each rod = 4cm 2 . End of copper rod is maintained at 100°C where as ends of brass and steel are kept at 0°C. Lengths of the copper,, brass and steel rods are 46, 13 and 12 cms respectively. The rods are thermally insulated from surroundings excepts at ends. Thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.12 CGS units respectively. Rate of heat flow through copper rod is:a)1.2 cal/sb)2.4 cal/sc)4.8 cal/sd)6.0 cal/sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Three rods of Copper, Brass and Steel are welded together to form a Y shaped structure. Area of cross - section of each rod = 4cm 2 . End of copper rod is maintained at 100°C where as ends of brass and steel are kept at 0°C. Lengths of the copper,, brass and steel rods are 46, 13 and 12 cms respectively. The rods are thermally insulated from surroundings excepts at ends. Thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.12 CGS units respectively. Rate of heat flow through copper rod is:a)1.2 cal/sb)2.4 cal/sc)4.8 cal/sd)6.0 cal/sCorrect answer is option 'C'. Can you explain this answer?.
Solutions for Three rods of Copper, Brass and Steel are welded together to form a Y shaped structure. Area of cross - section of each rod = 4cm 2 . End of copper rod is maintained at 100°C where as ends of brass and steel are kept at 0°C. Lengths of the copper,, brass and steel rods are 46, 13 and 12 cms respectively. The rods are thermally insulated from surroundings excepts at ends. Thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.12 CGS units respectively. Rate of heat flow through copper rod is:a)1.2 cal/sb)2.4 cal/sc)4.8 cal/sd)6.0 cal/sCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Three rods of Copper, Brass and Steel are welded together to form a Y shaped structure. Area of cross - section of each rod = 4cm 2 . End of copper rod is maintained at 100°C where as ends of brass and steel are kept at 0°C. Lengths of the copper,, brass and steel rods are 46, 13 and 12 cms respectively. The rods are thermally insulated from surroundings excepts at ends. Thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.12 CGS units respectively. Rate of heat flow through copper rod is:a)1.2 cal/sb)2.4 cal/sc)4.8 cal/sd)6.0 cal/sCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Three rods of Copper, Brass and Steel are welded together to form a Y shaped structure. Area of cross - section of each rod = 4cm 2 . End of copper rod is maintained at 100°C where as ends of brass and steel are kept at 0°C. Lengths of the copper,, brass and steel rods are 46, 13 and 12 cms respectively. The rods are thermally insulated from surroundings excepts at ends. Thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.12 CGS units respectively. Rate of heat flow through copper rod is:a)1.2 cal/sb)2.4 cal/sc)4.8 cal/sd)6.0 cal/sCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Three rods of Copper, Brass and Steel are welded together to form a Y shaped structure. Area of cross - section of each rod = 4cm 2 . End of copper rod is maintained at 100°C where as ends of brass and steel are kept at 0°C. Lengths of the copper,, brass and steel rods are 46, 13 and 12 cms respectively. The rods are thermally insulated from surroundings excepts at ends. Thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.12 CGS units respectively. Rate of heat flow through copper rod is:a)1.2 cal/sb)2.4 cal/sc)4.8 cal/sd)6.0 cal/sCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Three rods of Copper, Brass and Steel are welded together to form a Y shaped structure. Area of cross - section of each rod = 4cm 2 . End of copper rod is maintained at 100°C where as ends of brass and steel are kept at 0°C. Lengths of the copper,, brass and steel rods are 46, 13 and 12 cms respectively. The rods are thermally insulated from surroundings excepts at ends. Thermal conductivities of copper, brass and steel are 0.92, 0.26 and 0.12 CGS units respectively. Rate of heat flow through copper rod is:a)1.2 cal/sb)2.4 cal/sc)4.8 cal/sd)6.0 cal/sCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
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