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A solution contains substances A and B in h2o. Mole fraction of A= 0.05 , molarity of B = 7M , density of soln = 1.14 . Calculate molarity of A?
Verified Answer
A solution contains substances A and B in h2o. Mole fraction of A= 0.0...
Method to Solve :
Mole fraction of A, Xa = nA/nT= 0.05 = 5/100
It means 5 moles of A are present in 100 molesw of solution.Thus
nA + nB + H2O = 100
Let's suppose water is 100 ml
So no of moles of water is nH2O= 100/18 = 55.55 mol
nB = 100 - 55.55 - 5 = 39.45 mol
Now find the volume of solution.
The volume of solution = Moles of B / 7 = 39.45/7
= 5.63 L
Molarity of A = 5/5.63 = 0.88 M
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Most Upvoted Answer
A solution contains substances A and B in h2o. Mole fraction of A= 0.0...
Given Information:
Mole fraction of substance A: 0.05
Molarity of substance B: 7 M
Density of the solution: 1.14
Calculation:
To find the molarity of substance A, we can use the relationship between mole fraction, molarity, and density of the solution.
Mole fraction of A (XA) can be defined as the ratio of the number of moles of A to the total number of moles in the solution. Mathematically, it can be expressed as:
XA = moles of A / (moles of A + moles of B)
Given that the mole fraction of A is 0.05, we can rewrite the equation as:
0.05 = moles of A / (moles of A + moles of B)
Since the mole fraction is given, we can assume a total volume of the solution to be 100 mL in order to simplify the calculations.
Step 1: Calculation of moles of B:
The molarity of substance B is given as 7 M. Molarity is defined as moles of solute per liter of solution. Therefore, the moles of B can be calculated using the following formula:
moles of B = molarity of B * volume of solution
Assuming a total volume of 100 mL, the volume of solution can be converted to liters:
Volume of solution = 100 mL * (1 L / 1000 mL) = 0.1 L
Now, substituting the values into the formula:
moles of B = 7 M * 0.1 L = 0.7 moles
Step 2: Calculation of moles of A:
We can rearrange the equation for mole fraction to solve for the moles of A:
moles of A = XA * (moles of A + moles of B)
Substituting the given values:
moles of A = 0.05 * (moles of A + 0.7)
Expanding the equation:
moles of A = 0.05 * moles of A + 0.05 * 0.7
Simplifying the equation:
0.95 * moles of A = 0.05 * 0.7
moles of A = (0.05 * 0.7) / 0.95 = 0.03684 moles
Step 3: Calculation of molarity of A:
Molarity is defined as moles of solute per liter of solution. Therefore, to find the molarity of A, we need to divide the moles of A by the volume of the solution.
Assuming a total volume of 100 mL, the volume of solution can be converted to liters:
Volume of solution = 100 mL * (1 L / 1000 mL) = 0.1 L
Now, substituting the values into the formula:
Molarity of A = moles of A / volume of solution
Molarity of A = 0.03684 moles / 0.1 L = 0.3684 M
Conclusion:
The molarity of substance A in the solution is 0.3684 M.
Mole fraction of substance A: 0.05
Molarity of substance B: 7 M
Density of the solution: 1.14
Calculation:
To find the molarity of substance A, we can use the relationship between mole fraction, molarity, and density of the solution.
Mole fraction of A (XA) can be defined as the ratio of the number of moles of A to the total number of moles in the solution. Mathematically, it can be expressed as:
XA = moles of A / (moles of A + moles of B)
Given that the mole fraction of A is 0.05, we can rewrite the equation as:
0.05 = moles of A / (moles of A + moles of B)
Since the mole fraction is given, we can assume a total volume of the solution to be 100 mL in order to simplify the calculations.
Step 1: Calculation of moles of B:
The molarity of substance B is given as 7 M. Molarity is defined as moles of solute per liter of solution. Therefore, the moles of B can be calculated using the following formula:
moles of B = molarity of B * volume of solution
Assuming a total volume of 100 mL, the volume of solution can be converted to liters:
Volume of solution = 100 mL * (1 L / 1000 mL) = 0.1 L
Now, substituting the values into the formula:
moles of B = 7 M * 0.1 L = 0.7 moles
Step 2: Calculation of moles of A:
We can rearrange the equation for mole fraction to solve for the moles of A:
moles of A = XA * (moles of A + moles of B)
Substituting the given values:
moles of A = 0.05 * (moles of A + 0.7)
Expanding the equation:
moles of A = 0.05 * moles of A + 0.05 * 0.7
Simplifying the equation:
0.95 * moles of A = 0.05 * 0.7
moles of A = (0.05 * 0.7) / 0.95 = 0.03684 moles
Step 3: Calculation of molarity of A:
Molarity is defined as moles of solute per liter of solution. Therefore, to find the molarity of A, we need to divide the moles of A by the volume of the solution.
Assuming a total volume of 100 mL, the volume of solution can be converted to liters:
Volume of solution = 100 mL * (1 L / 1000 mL) = 0.1 L
Now, substituting the values into the formula:
Molarity of A = moles of A / volume of solution
Molarity of A = 0.03684 moles / 0.1 L = 0.3684 M
Conclusion:
The molarity of substance A in the solution is 0.3684 M.
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A solution contains substances A and B in h2o. Mole fraction of A= 0.05 , molarity of B = 7M , density of soln = 1.14 . Calculate molarity of A?
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A solution contains substances A and B in h2o. Mole fraction of A= 0.05 , molarity of B = 7M , density of soln = 1.14 . Calculate molarity of A? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A solution contains substances A and B in h2o. Mole fraction of A= 0.05 , molarity of B = 7M , density of soln = 1.14 . Calculate molarity of A? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution contains substances A and B in h2o. Mole fraction of A= 0.05 , molarity of B = 7M , density of soln = 1.14 . Calculate molarity of A?.
A solution contains substances A and B in h2o. Mole fraction of A= 0.05 , molarity of B = 7M , density of soln = 1.14 . Calculate molarity of A? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A solution contains substances A and B in h2o. Mole fraction of A= 0.05 , molarity of B = 7M , density of soln = 1.14 . Calculate molarity of A? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution contains substances A and B in h2o. Mole fraction of A= 0.05 , molarity of B = 7M , density of soln = 1.14 . Calculate molarity of A?.
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