JEE Exam > JEE Questions > A Carnot engine, whose efficiency is 40%, tak...
Start Learning for Free
A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :
- a)efficiency of Carnot engine cannot be made larger than 50%
- b)1200 K
- c)750 K
- d)600 K
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A Carnot engine, whose efficiency is 40%, takes in heat from a source ...
on solving we get T2 = 750 K
Most Upvoted Answer
A Carnot engine, whose efficiency is 40%, takes in heat from a source ...
Introduction:
The Carnot engine is an idealized heat engine that operates between two thermal reservoirs, a heat source and a heat sink. It follows the Carnot cycle, which consists of four reversible processes: isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression. The efficiency of a Carnot engine is given by the equation:
Efficiency = 1 - (Tc/Th)
Where Tc is the temperature of the heat sink and Th is the temperature of the heat source.
Given:
Efficiency of the Carnot engine = 40%
Temperature of the heat source (Th) = 500K
To find:
Temperature of the heat sink (Tc) for an efficiency of 60%
Solution:
To find the temperature of the heat sink for an efficiency of 60%, we can rearrange the efficiency equation as follows:
Tc/Th = 1 - Efficiency
Let's substitute the given values:
Tc/500 = 1 - 0.4
Simplifying the equation, we get:
Tc/500 = 0.6
Now, we can solve for Tc:
Tc = 0.6 * 500
Tc = 300K
Conclusion:
Therefore, the temperature of the heat sink (Tc) for an efficiency of 60% is 300K.
The Carnot engine is an idealized heat engine that operates between two thermal reservoirs, a heat source and a heat sink. It follows the Carnot cycle, which consists of four reversible processes: isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression. The efficiency of a Carnot engine is given by the equation:
Efficiency = 1 - (Tc/Th)
Where Tc is the temperature of the heat sink and Th is the temperature of the heat source.
Given:
Efficiency of the Carnot engine = 40%
Temperature of the heat source (Th) = 500K
To find:
Temperature of the heat sink (Tc) for an efficiency of 60%
Solution:
To find the temperature of the heat sink for an efficiency of 60%, we can rearrange the efficiency equation as follows:
Tc/Th = 1 - Efficiency
Let's substitute the given values:
Tc/500 = 1 - 0.4
Simplifying the equation, we get:
Tc/500 = 0.6
Now, we can solve for Tc:
Tc = 0.6 * 500
Tc = 300K
Conclusion:
Therefore, the temperature of the heat sink (Tc) for an efficiency of 60% is 300K.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :a)efficiency of Carnot engine cannot be made larger than 50%b)1200 Kc)750 Kd)600 KCorrect answer is option 'C'. Can you explain this answer?
Question Description
A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :a)efficiency of Carnot engine cannot be made larger than 50%b)1200 Kc)750 Kd)600 KCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :a)efficiency of Carnot engine cannot be made larger than 50%b)1200 Kc)750 Kd)600 KCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :a)efficiency of Carnot engine cannot be made larger than 50%b)1200 Kc)750 Kd)600 KCorrect answer is option 'C'. Can you explain this answer?.
A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :a)efficiency of Carnot engine cannot be made larger than 50%b)1200 Kc)750 Kd)600 KCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :a)efficiency of Carnot engine cannot be made larger than 50%b)1200 Kc)750 Kd)600 KCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :a)efficiency of Carnot engine cannot be made larger than 50%b)1200 Kc)750 Kd)600 KCorrect answer is option 'C'. Can you explain this answer?.
Solutions for A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :a)efficiency of Carnot engine cannot be made larger than 50%b)1200 Kc)750 Kd)600 KCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :a)efficiency of Carnot engine cannot be made larger than 50%b)1200 Kc)750 Kd)600 KCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :a)efficiency of Carnot engine cannot be made larger than 50%b)1200 Kc)750 Kd)600 KCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :a)efficiency of Carnot engine cannot be made larger than 50%b)1200 Kc)750 Kd)600 KCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :a)efficiency of Carnot engine cannot be made larger than 50%b)1200 Kc)750 Kd)600 KCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) temperature must be :a)efficiency of Carnot engine cannot be made larger than 50%b)1200 Kc)750 Kd)600 KCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup