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In rhombic sulphur , s-atoms are joining into s8 molecules with density 2.07 g/cm(3).Number of s8 molecules in Crystal of 0.568 mm(3)is?
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In rhombic sulphur , s-atoms are joining into s8 molecules with densit...
Calculation of Number of S8 Molecules in Rhombic Sulphur Crystal

Given:

  • Density of Rhombic Sulphur = 2.07 g/cm3

  • Volume of Crystal = 0.568 mm3



Formula:

  • Number of S8 molecules = (Avogadro's number x Volume of Crystal x Density of Rhombic Sulphur) / (Molar mass of S8 x Volume of S8 molecule)

  • Avogadro's number = 6.022 x 1023 molecules/mol

  • Molar mass of S8 = 256 g/mol

  • Volume of S8 molecule = (4/3) x π x (3.28 Å)3 = 1.03 x 10-25 cm3



Calculation:

  • Volume of Crystal (in cm3) = 0.568 mm3 x (1 cm / 10 mm)3 = 5.68 x 10-4 cm3

  • Number of S8 molecules = (6.022 x 1023 molecules/mol x 5.68 x 10-4 cm3 x 2.07 g/cm3) / (256 g/mol x 1.03 x 10-25 cm3)

  • Number of S8 molecules = 1.11 x 1020



Answer:

  • Number of S8 molecules in Rhombic Sulphur Crystal of 0.568 mm3 is 1.11 x 1020.

Community Answer
In rhombic sulphur , s-atoms are joining into s8 molecules with densit...
I got my answer as 27.556×10^(17). Please give me the correct answer.
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In rhombic sulphur , s-atoms are joining into s8 molecules with density 2.07 g/cm(3).Number of s8 molecules in Crystal of 0.568 mm(3)is?
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