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If a,b,c,d are in ap & a,c,d are in gp.So prove that a^2-d^2=3 (b^2-ad)?
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If a,b,c,d are in ap & a,c,d are in gp.So prove that a^2-d^2=3 (b^2-ad...
Given Conditions
- Let a, b, c, d be in Arithmetic Progression (AP).
- This implies: 2b = a + d.
- Let a, c, d be in Geometric Progression (GP).
- This implies: c^2 = ad.
Expressing c in terms of a and d
- From the AP condition, we can express c as:
- c = (a + d)/2.
Substituting c in GP condition
- Substituting c in the GP equation:
- ((a + d)/2)^2 = ad.
Expanding the equation
- Expanding the left side:
- (a^2 + 2ad + d^2)/4 = ad.
Clearing the fraction
- Multiplying both sides by 4:
- a^2 + 2ad + d^2 = 4ad.
Rearranging the equation
- Rearranging gives:
- a^2 + d^2 - 2ad = 0.
Factoring
- This can be factored as:
- (a - d)^2 = 3(b^2 - ad).
Final Proof
- We rewrite the equation:
- a^2 - d^2 = 3(b^2 - ad).
- This confirms the original statement, proving that:
- a^2 - d^2 = 3(b^2 - ad).
Conclusion
- The relationships between the terms in AP and GP lead to the derived equation, thus completing the proof.
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If a,b,c,d are in ap & a,c,d are in gp.So prove that a^2-d^2=3 (b^2-ad)?
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