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The enthalpy of neutralization of which of the following acids and bases is nearly -13.6 kcal:
  • a)
    HCN and NaOH
  • b)
    HClandKOH
  • c)
    HCl and NaOH
  • d)
    HCl and NH4OH
Correct answer is option 'B,C'. Can you explain this answer?
Most Upvoted Answer
The enthalpy of neutralization of which of the following acids and bas...
**Enthalpy of Neutralization**

The enthalpy of neutralization is the heat change that occurs when an acid and a base react to form one mole of water. It is a measure of the heat energy released or absorbed during the neutralization reaction. The enthalpy of neutralization is typically negative, indicating an exothermic reaction where heat is released.

**Calculating Enthalpy of Neutralization**

To calculate the enthalpy of neutralization, we need to consider the balanced chemical equation for the neutralization reaction and the enthalpy change associated with each reaction. The enthalpy change is given by the formula:

ΔH = q / n

Where:
ΔH = Enthalpy change
q = Heat absorbed or released during the reaction
n = Number of moles of the limiting reactant

**Options Analysis**

a) HCN and NaOH: HCN is a weak acid and NaOH is a strong base. The enthalpy of neutralization for this combination is not expected to be -13.6 kcal.

b) HCl and KOH: Both HCl and KOH are strong acids and bases, respectively. The enthalpy of neutralization for this combination is expected to be -13.6 kcal.

c) HCl and NaOH: Both HCl and NaOH are strong acids and bases, respectively. The enthalpy of neutralization for this combination is expected to be -13.6 kcal.

d) HCl and NH4OH: HCl is a strong acid, but NH4OH is a weak base. The enthalpy of neutralization for this combination is not expected to be -13.6 kcal.

**Conclusion**

Based on the analysis, options b) and c) are the correct answers. The enthalpy of neutralization of HCl and KOH as well as HCl and NaOH is expected to be nearly -13.6 kcal.
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Community Answer
The enthalpy of neutralization of which of the following acids and bas...
Because enthalpy of neutralization of strong acid with strong base is 13.6 kcal. If we take either weak acid or weak base, then enthalpy will be decreased as some heat is consupted in more dissotiation of weak base/acid.
Hence in B and C option both are strong
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The enthalpy of neutralization of which of the following acids and bases is nearly -13.6 kcal:a)HCN and NaOHb)HClandKOHc)HCl and NaOHd)HCl and NH4OHCorrect answer is option 'B,C'. Can you explain this answer?
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