Class 12 Exam  >  Class 12 Questions  >  When light of wavelength 300 nm (nanometer) f... Start Learning for Free
When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectronsare liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creatingphotoemission. What is the ratio of the work functions of the two emitters?  [1993]
  • a)
    1 : 2
  • b)
    2 : 1
  • c)
    4 : 1
  • d)
    1 : 4
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
When light of wavelength 300 nm (nanometer) falls on a photoelectric e...
Work function   ϕ=hc​/λ
⟹ ϕ12​ ​​=​λ2​​/λ1
Given :  λ1​=300 nm          λ2​=600 nm
∴  ​ϕ1/ ϕ2 ​​=600/300 ​=2
Explore Courses for Class 12 exam
When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectronsare liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creatingphotoemission. What is the ratio of the work functions of the two emitters? [1993]a)1 : 2b)2 : 1c)4 : 1d)1 : 4Correct answer is option 'B'. Can you explain this answer?
Question Description
When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectronsare liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creatingphotoemission. What is the ratio of the work functions of the two emitters? [1993]a)1 : 2b)2 : 1c)4 : 1d)1 : 4Correct answer is option 'B'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectronsare liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creatingphotoemission. What is the ratio of the work functions of the two emitters? [1993]a)1 : 2b)2 : 1c)4 : 1d)1 : 4Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectronsare liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creatingphotoemission. What is the ratio of the work functions of the two emitters? [1993]a)1 : 2b)2 : 1c)4 : 1d)1 : 4Correct answer is option 'B'. Can you explain this answer?.
Solutions for When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectronsare liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creatingphotoemission. What is the ratio of the work functions of the two emitters? [1993]a)1 : 2b)2 : 1c)4 : 1d)1 : 4Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectronsare liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creatingphotoemission. What is the ratio of the work functions of the two emitters? [1993]a)1 : 2b)2 : 1c)4 : 1d)1 : 4Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectronsare liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creatingphotoemission. What is the ratio of the work functions of the two emitters? [1993]a)1 : 2b)2 : 1c)4 : 1d)1 : 4Correct answer is option 'B'. Can you explain this answer?, a detailed solution for When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectronsare liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creatingphotoemission. What is the ratio of the work functions of the two emitters? [1993]a)1 : 2b)2 : 1c)4 : 1d)1 : 4Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectronsare liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creatingphotoemission. What is the ratio of the work functions of the two emitters? [1993]a)1 : 2b)2 : 1c)4 : 1d)1 : 4Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice When light of wavelength 300 nm (nanometer) falls on a photoelectric emitter, photoelectronsare liberated. For another emitter, however, light of 600 nm wavelength is sufficient for creatingphotoemission. What is the ratio of the work functions of the two emitters? [1993]a)1 : 2b)2 : 1c)4 : 1d)1 : 4Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.
Explore Courses for Class 12 exam
Signup to solve all Doubts
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev