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A proton carrying 1 MeV kinetic energy ismoving in a circular path of radius R in uniformmagnetic field. What should be the energy of an α -particle to describe a circle of same radius inthe same field? [2012M]
- a)2 MeV
- b)1 MeV
- c)0.5 MeV
- d)4 MeV
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A proton carrying 1 MeV kinetic energy ismoving in a circular path of ...
According to the principal of circular motion in a magnetic field
but R = Rα (given)
Thus K = K' = 1 MeV
Most Upvoted Answer
A proton carrying 1 MeV kinetic energy ismoving in a circular path of ...
Given Information:
A proton carrying 1 MeV kinetic energy is moving in a circular path of radius R in a uniform magnetic field.
Explanation:
When a charged particle moves in a magnetic field, it experiences a force perpendicular to its velocity, causing it to move in a circular path. The centripetal force required for this circular motion is provided by the magnetic force acting on the particle.
Formula for Kinetic Energy of a Charged Particle:
The kinetic energy (K) of a charged particle moving in a magnetic field is given by the formula:
K = qVB
where,
q = charge of the particle
V = velocity of the particle
B = magnetic field strength
Relationship between Energy and Radius of Circular Path:
The radius of the circular path followed by a charged particle in a magnetic field is given by the formula:
R = (mv) / (qB)
where,
m = mass of the particle
Determination of α-particle energy:
For the proton carrying 1 MeV kinetic energy, the energy of an α-particle can be determined using the formula for kinetic energy.
Given that the radius of the circular path is the same for both particles, the energy of the α-particle can be calculated using the same formula by substituting the charge and mass of the α-particle.
Therefore, the energy of the α-particle to describe a circle of the same radius in the same magnetic field is 1 MeV, which is the same as that of the proton. Hence, the correct answer is option 'b) 1 MeV'.
A proton carrying 1 MeV kinetic energy is moving in a circular path of radius R in a uniform magnetic field.
Explanation:
When a charged particle moves in a magnetic field, it experiences a force perpendicular to its velocity, causing it to move in a circular path. The centripetal force required for this circular motion is provided by the magnetic force acting on the particle.
Formula for Kinetic Energy of a Charged Particle:
The kinetic energy (K) of a charged particle moving in a magnetic field is given by the formula:
K = qVB
where,
q = charge of the particle
V = velocity of the particle
B = magnetic field strength
Relationship between Energy and Radius of Circular Path:
The radius of the circular path followed by a charged particle in a magnetic field is given by the formula:
R = (mv) / (qB)
where,
m = mass of the particle
Determination of α-particle energy:
For the proton carrying 1 MeV kinetic energy, the energy of an α-particle can be determined using the formula for kinetic energy.
Given that the radius of the circular path is the same for both particles, the energy of the α-particle can be calculated using the same formula by substituting the charge and mass of the α-particle.
Therefore, the energy of the α-particle to describe a circle of the same radius in the same magnetic field is 1 MeV, which is the same as that of the proton. Hence, the correct answer is option 'b) 1 MeV'.
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A proton carrying 1 MeV kinetic energy ismoving in a circular path of radius R in uniformmagnetic field. What should be the energy of an α -particle to describe a circle of same radius inthe same field? [2012M]a)2 MeVb)1 MeVc)0.5 MeVd)4 MeVCorrect answer is option 'B'. Can you explain this answer? for Class 12 2026 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A proton carrying 1 MeV kinetic energy ismoving in a circular path of radius R in uniformmagnetic field. What should be the energy of an α -particle to describe a circle of same radius inthe same field? [2012M]a)2 MeVb)1 MeVc)0.5 MeVd)4 MeVCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A proton carrying 1 MeV kinetic energy ismoving in a circular path of radius R in uniformmagnetic field. What should be the energy of an α -particle to describe a circle of same radius inthe same field? [2012M]a)2 MeVb)1 MeVc)0.5 MeVd)4 MeVCorrect answer is option 'B'. Can you explain this answer?.
A proton carrying 1 MeV kinetic energy ismoving in a circular path of radius R in uniformmagnetic field. What should be the energy of an α -particle to describe a circle of same radius inthe same field? [2012M]a)2 MeVb)1 MeVc)0.5 MeVd)4 MeVCorrect answer is option 'B'. Can you explain this answer? for Class 12 2026 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A proton carrying 1 MeV kinetic energy ismoving in a circular path of radius R in uniformmagnetic field. What should be the energy of an α -particle to describe a circle of same radius inthe same field? [2012M]a)2 MeVb)1 MeVc)0.5 MeVd)4 MeVCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A proton carrying 1 MeV kinetic energy ismoving in a circular path of radius R in uniformmagnetic field. What should be the energy of an α -particle to describe a circle of same radius inthe same field? [2012M]a)2 MeVb)1 MeVc)0.5 MeVd)4 MeVCorrect answer is option 'B'. Can you explain this answer?.
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