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A three-phase three pulse type controlled converter is constructed using 3 SCR devices. The circuit is supplying an R load with α < 30°. As such, each SCR device would conduct for
- a)60° each cycle
- b)120° each cycle
- c)180° each cycle
- d)360° each cycle
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A three-phase three pulse type controlled converter is constructed usi...
Each conduct for 120° per cycle is the firing angle is less than 30°. 120 x 3 = 360°.
Most Upvoted Answer
A three-phase three pulse type controlled converter is constructed usi...
A line voltage of 480V. Each SCR has a forward voltage drop of 1.5V and a maximum current rating of 50A. The load resistance is 10Ω. Determine the maximum power that can be delivered to the load.
To determine the maximum power that can be delivered to the load, we need to calculate the maximum current that can flow through the SCR devices.
Since each SCR has a maximum current rating of 50A, the maximum current that can flow through the load is limited by the SCR with the lowest current rating. Therefore, the maximum current that can flow through the load is 50A.
Using Ohm's Law, we can calculate the maximum voltage across the load:
V = I * R
V = 50A * 10Ω
V = 500V
However, since each SCR has a forward voltage drop of 1.5V, the actual voltage across the load would be:
V_load = V_line - (3 * V_drop)
V_load = 480V - (3 * 1.5V)
V_load = 480V - 4.5V
V_load = 475.5V
Finally, we can calculate the maximum power delivered to the load:
P = (V_load^2) / R
P = (475.5V^2) / 10Ω
P = 226.5025kW
Therefore, the maximum power that can be delivered to the load is approximately 226.5025 kW.
To determine the maximum power that can be delivered to the load, we need to calculate the maximum current that can flow through the SCR devices.
Since each SCR has a maximum current rating of 50A, the maximum current that can flow through the load is limited by the SCR with the lowest current rating. Therefore, the maximum current that can flow through the load is 50A.
Using Ohm's Law, we can calculate the maximum voltage across the load:
V = I * R
V = 50A * 10Ω
V = 500V
However, since each SCR has a forward voltage drop of 1.5V, the actual voltage across the load would be:
V_load = V_line - (3 * V_drop)
V_load = 480V - (3 * 1.5V)
V_load = 480V - 4.5V
V_load = 475.5V
Finally, we can calculate the maximum power delivered to the load:
P = (V_load^2) / R
P = (475.5V^2) / 10Ω
P = 226.5025kW
Therefore, the maximum power that can be delivered to the load is approximately 226.5025 kW.
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