A bomb of mass 30 kg at rest explodes into two pieces of masses 18 kg ...
A bomb of mass 30 kg at rest explodes into two pieces of masses 18 kg ...
To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the explosion is equal to the total momentum after the explosion.
Let's assume the initial velocity of the 12 kg mass is v2 and the velocity of the 18 kg mass is v1.
Before the explosion:
The total momentum before the explosion is zero since the bomb is at rest:
Total momentum before = 0
After the explosion:
The momentum of the 18 kg mass is given by:
Momentum of 18 kg mass = mass of 18 kg * velocity of 18 kg mass = 18 kg * 6 m/s = 108 kg*m/s
The momentum of the 12 kg mass is given by:
Momentum of 12 kg mass = mass of 12 kg * velocity of 12 kg mass = 12 kg * v2
The total momentum after the explosion is the sum of the momenta of the two masses:
Total momentum after = Momentum of 18 kg mass + Momentum of 12 kg mass
According to the conservation of momentum principle:
Total momentum before = Total momentum after
0 = 108 kg*m/s + 12 kg * v2
Simplifying the equation:
12 kg * v2 = -108 kg*m/s
v2 = -108 kg*m/s / 12 kg
v2 = -9 m/s
Therefore, the velocity of the 12 kg mass is -9 m/s.