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An LCR series circuit is connected to a source of alternating current. At resonance, the applied voltage and the current flowing through the circuit will have a phase difference of [1994]
  • a)
    π
  • b)
    π/2
  • c)
    π/4
  • d)
    0
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
An LCR series circuit is connected to a source of alternating current....
At resonance,  The circuit
behaves as if it contains R only. So, phase
difference = 0
At resonance, impedance is minimum Zmin =
R and current is maximum, given by 
It is interesting to note that before resonance
the current leads the applied emf, at
resonance it is in phase, and after resonance
it lags behind the emf. LCR series circuit is
also called as acceptor circuit and parallel
LCR circuit is called rejector circuit.
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Most Upvoted Answer
An LCR series circuit is connected to a source of alternating current....
Phase Difference at Resonance in an LCR Circuit
- Resonance in an LCR Circuit:
- At resonance in an LCR series circuit, the inductive reactance (XL) and capacitive reactance (XC) cancel each other out, leaving only the resistance (R) in the circuit.
- This results in the impedance being purely resistive at resonance.
- Phase Difference:
- In a purely resistive circuit, like at resonance in an LCR circuit, the voltage and current are in phase with each other.
- This means that the phase difference between the applied voltage and the current flowing through the circuit is 0 degrees.
- The voltage and current reach their maximum and zero values at the same time during each cycle of the alternating current.
- Answer Explanation:
- Option 'D' (0) is the correct answer because at resonance in an LCR circuit, the voltage and current are in phase with each other.
- There is no phase difference between the voltage and current in a purely resistive circuit, which occurs at resonance in an LCR circuit.
Therefore, at resonance in an LCR series circuit connected to a source of alternating current, the applied voltage and the current flowing through the circuit will have a phase difference of 0 degrees.
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An LCR series circuit is connected to a source of alternating current. At resonance, the applied voltage and the current flowing through the circuit will have a phase difference of [1994]a)πb)π/2c)π/4d)0Correct answer is option 'D'. Can you explain this answer?
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