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Two pith balls carrying equal charges are suspended from a common point by strings of equal length. The equilibrium separation
between them is r. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now become
[NEET 2013]
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'A'. Can you explain this answer?
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Two pith balls carrying equal charges are suspended from a common poin...
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Two pith balls carrying equal charges are suspended from a common point by strings of equal length. The equilibrium separationbetween them is r. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now become[NEET 2013]a)b)c)d)Correct answer is option 'A'. Can you explain this answer?
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Two pith balls carrying equal charges are suspended from a common point by strings of equal length. The equilibrium separationbetween them is r. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now become[NEET 2013]a)b)c)d)Correct answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two pith balls carrying equal charges are suspended from a common point by strings of equal length. The equilibrium separationbetween them is r. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now become[NEET 2013]a)b)c)d)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two pith balls carrying equal charges are suspended from a common point by strings of equal length. The equilibrium separationbetween them is r. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now become[NEET 2013]a)b)c)d)Correct answer is option 'A'. Can you explain this answer?.
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