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The electric potential V at any point (x, y, z), all inmeters in space is given by V = 4x2 volt. Theelectric field at the point (1, 0, 2) in volt/meteris [2011M]
  • a)
    8 along positive X-axis
  • b)
    16 along negative X-axis
  • c)
    16 along positive X-axis
  • d)
    8 along negative X-axis
Correct answer is option 'D'. Can you explain this answer?
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The electric potential V at any point (x, y, z), all inmeters in space...
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The electric potential V at any point (x, y, z), all inmeters in space...
Given: Electric potential V = 4x² V at any point (x, y, z).

To find: Electric field at point (1, 0, 2) in volt/meter.

Formula: Electric field E = -∇V, where ∇ is the gradient operator.

Calculation:

- Taking the gradient of V, we get:

∇V = (∂V/∂x)î + (∂V/∂y)ĵ + (∂V/∂z)k

∂V/∂x = 8x, ∂V/∂y = 0, ∂V/∂z = 0

∇V = 8xî

- Now, substituting the given point (1, 0, 2) in the above equation, we get:

∇V = 8(1)î = 8î

- Finally, using the formula E = -∇V, we get:

E = -8î

Since the x-component of the electric field is negative, the electric field is directed along the negative x-axis.

Therefore, the correct option is (d) 8 along negative X-axis.
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