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There is an electric field E in x-direction. If the work done on moving a charge of 0.2 C through a distance of 2 m along a line making an angle 60° with x-axis is 4J, then what is the value of E? [1995]
- a)3 N/C
- b)4 N/C
- c)5 N/C
- d)20 N/C
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
There is an electric field E in x-direction. If the work done on movin...
Charge (q) = 0.2 C; Distance (d) = 2m; Angle
θ = 60º and work done (W) = 4J.
Work done in moving the charge (W)
= F.d cos θ = qEd cos θ
θ = 60º and work done (W) = 4J.
Work done in moving the charge (W)
= F.d cos θ = qEd cos θ
or
Most Upvoted Answer
There is an electric field E in x-direction. If the work done on movin...
Degrees with the x-axis is 10 J, then what is the magnitude of the electric field E?
We can start by using the formula for the work done by an electric field on a charge:
W = qEd cos(theta)
where W is the work done, q is the charge, E is the electric field, d is the distance moved, and theta is the angle between the direction of movement and the electric field.
In this case, we know W = 10 J, q = 0.2 C, d = 2 m, and theta = 60 degrees. We want to solve for E.
First, we need to convert the angle to radians:
theta = 60 degrees * (pi/180) = pi/3 radians
Now we can plug in the values and solve for E:
10 J = (0.2 C)E(2 m)cos(pi/3)
10 J = (0.2 C)E(2 m)(0.5)
10 J = 0.2 CE
E = 10 J / (0.2 C * 2 m * 0.5)
E = 25 N/C
Therefore, the magnitude of the electric field E is 25 N/C.
We can start by using the formula for the work done by an electric field on a charge:
W = qEd cos(theta)
where W is the work done, q is the charge, E is the electric field, d is the distance moved, and theta is the angle between the direction of movement and the electric field.
In this case, we know W = 10 J, q = 0.2 C, d = 2 m, and theta = 60 degrees. We want to solve for E.
First, we need to convert the angle to radians:
theta = 60 degrees * (pi/180) = pi/3 radians
Now we can plug in the values and solve for E:
10 J = (0.2 C)E(2 m)cos(pi/3)
10 J = (0.2 C)E(2 m)(0.5)
10 J = 0.2 CE
E = 10 J / (0.2 C * 2 m * 0.5)
E = 25 N/C
Therefore, the magnitude of the electric field E is 25 N/C.
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There is an electric field E in x-direction. If the work done on moving a charge of 0.2 C through a distance of 2 m along a line making an angle 60° with x-axis is 4J, then what is the value of E? [1995]a)3 N/Cb)4 N/Cc)5 N/Cd)20 N/CCorrect answer is option 'D'. Can you explain this answer? for Class 12 2026 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about There is an electric field E in x-direction. If the work done on moving a charge of 0.2 C through a distance of 2 m along a line making an angle 60° with x-axis is 4J, then what is the value of E? [1995]a)3 N/Cb)4 N/Cc)5 N/Cd)20 N/CCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There is an electric field E in x-direction. If the work done on moving a charge of 0.2 C through a distance of 2 m along a line making an angle 60° with x-axis is 4J, then what is the value of E? [1995]a)3 N/Cb)4 N/Cc)5 N/Cd)20 N/CCorrect answer is option 'D'. Can you explain this answer?.
There is an electric field E in x-direction. If the work done on moving a charge of 0.2 C through a distance of 2 m along a line making an angle 60° with x-axis is 4J, then what is the value of E? [1995]a)3 N/Cb)4 N/Cc)5 N/Cd)20 N/CCorrect answer is option 'D'. Can you explain this answer? for Class 12 2026 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about There is an electric field E in x-direction. If the work done on moving a charge of 0.2 C through a distance of 2 m along a line making an angle 60° with x-axis is 4J, then what is the value of E? [1995]a)3 N/Cb)4 N/Cc)5 N/Cd)20 N/CCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There is an electric field E in x-direction. If the work done on moving a charge of 0.2 C through a distance of 2 m along a line making an angle 60° with x-axis is 4J, then what is the value of E? [1995]a)3 N/Cb)4 N/Cc)5 N/Cd)20 N/CCorrect answer is option 'D'. Can you explain this answer?.
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