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If y = –2x2 – 6x + 9, then
  • a)
    Maximum value of y is – 11 and it occurs at x = 2
  • b)
    Minimum value of y is – 11 and it occurs at x = 2
  • c)
    Maximum value of y is 13.5 and it occurs at x = –1.5
  • d)
    Minimum value of y is 13.5 and it occurs atx = –1.5
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
If y = –2x2–6x + 9, thena)Maximum value of y is –11 ...
y = -2x2 - 6x + 9
dy/dx = -4x - 6
Put dy/dx = 0
-4x - 6 = 0
x = -3/2   = 1.5
d2y/dx2 = -4 < 0  (Maximum point)
Max value = -2(-1.5)2 - 6(-1.5) + 9 
                  = 13.5
Max value of x = -1.5
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If y = –2x2–6x + 9, thena)Maximum value of y is –11 ...
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If y = –2x2–6x + 9, thena)Maximum value of y is –11 ...
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If y = –2x2–6x + 9, thena)Maximum value of y is –11 and it occurs at x = 2b)Minimum value of y is –11 and it occurs at x = 2c)Maximum value of y is 13.5 and it occurs at x = –1.5d)Minimum value of y is 13.5 and it occurs atx = –1.5Correct answer is option 'C'. Can you explain this answer?
Question Description
If y = –2x2–6x + 9, thena)Maximum value of y is –11 and it occurs at x = 2b)Minimum value of y is –11 and it occurs at x = 2c)Maximum value of y is 13.5 and it occurs at x = –1.5d)Minimum value of y is 13.5 and it occurs atx = –1.5Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If y = –2x2–6x + 9, thena)Maximum value of y is –11 and it occurs at x = 2b)Minimum value of y is –11 and it occurs at x = 2c)Maximum value of y is 13.5 and it occurs at x = –1.5d)Minimum value of y is 13.5 and it occurs atx = –1.5Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If y = –2x2–6x + 9, thena)Maximum value of y is –11 and it occurs at x = 2b)Minimum value of y is –11 and it occurs at x = 2c)Maximum value of y is 13.5 and it occurs at x = –1.5d)Minimum value of y is 13.5 and it occurs atx = –1.5Correct answer is option 'C'. Can you explain this answer?.
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