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If a positive charge moves opposite to the direction of the electric field
- a)Field does positive work on charge,potential energy decreases
- b)Field does negative work on charge,potential energy increases
- c)Field does negative work on charge,potential energy decreases
- d)Field does positive work on charge,potential energy increases
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
If a positive charge moves opposite to the direction of the electric f...
Explanation:A positive charge experiences a force in the direction of the field. If it moves opposite to the direction of the field, negative work is done by the electric field on the charge. Potential energy of the charge increases since an external source is required to do work on the charge against the direction of the field, and the work done is stored in the charge as its potential energy.
Most Upvoted Answer
If a positive charge moves opposite to the direction of the electric f...
Explanation:
When a positive charge moves opposite to the direction of the electric field, the electric field exerts a force on the charge. The direction of the force is opposite to the direction of the electric field. Therefore, the work done by the electric field on the charge is given by:
W = F*d*cosθ
where W is the work done, F is the force, d is the displacement of the charge, and θ is the angle between the force and the displacement.
Since the charge moves opposite to the direction of the electric field, the angle between the force and the displacement is 180 degrees. Therefore, cosθ = -1.
Substituting this value in the above equation, we get:
W = -F*d
Since the force is in the opposite direction to the displacement, the work done by the electric field is negative.
Now, the potential energy of a charge in an electric field is given by:
U = q*V
where U is the potential energy, q is the charge, and V is the potential difference.
When a positive charge moves opposite to the direction of the electric field, its potential energy increases. This is because the charge moves to a region of higher potential.
Therefore, the correct option is (B): Field does negative work on charge, potential energy increases.
When a positive charge moves opposite to the direction of the electric field, the electric field exerts a force on the charge. The direction of the force is opposite to the direction of the electric field. Therefore, the work done by the electric field on the charge is given by:
W = F*d*cosθ
where W is the work done, F is the force, d is the displacement of the charge, and θ is the angle between the force and the displacement.
Since the charge moves opposite to the direction of the electric field, the angle between the force and the displacement is 180 degrees. Therefore, cosθ = -1.
Substituting this value in the above equation, we get:
W = -F*d
Since the force is in the opposite direction to the displacement, the work done by the electric field is negative.
Now, the potential energy of a charge in an electric field is given by:
U = q*V
where U is the potential energy, q is the charge, and V is the potential difference.
When a positive charge moves opposite to the direction of the electric field, its potential energy increases. This is because the charge moves to a region of higher potential.
Therefore, the correct option is (B): Field does negative work on charge, potential energy increases.
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If a positive charge moves opposite to the direction of the electric fielda)Field does positive work on charge,potential energy decreasesb)Field does negative work on charge,potential energy increasesc)Field does negative work on charge,potential energy decreasesd)Field does positive work on charge,potential energy increasesCorrect answer is option 'B'. Can you explain this answer?
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