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A vessel contains a mixture of H2 and N2 gas. The density of the gas mixture is 0.2g/L at 300K and 1atm. Assuming that both the gases behave ideally,the mole fraction of N2(g) in the vessel is___. (Final answer should be rounded off to two decimal places) [Given,R=0.082L.atm.mol^-1.K^-1, atomic weight of hydrogen=1 and atomic weight of nitrogen=14]?

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YOGESH SHARMA
Sep 25, 2019 |

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A vessel contains a mixture of H2 and N2 gas. The density of the gas mixture is 0.2g/L at 300K and 1atm. Assuming that both the gases behave ideally,the mole fraction of N2(g) in the vessel is___. (Final answer should be rounded off to two decimal places) [Given,R=0.082L.atm.mol^-1.K^-1, atomic weight of hydrogen=1 and atomic weight of nitrogen=14]?

Ans.

Given: density of mixture=0.2g/L ,T=300K,P=1atm

Using formula d=PM/RT

Hence, M= (dxRxT)/P

M=(0.2x0.0821x300)/1

M=4.926g

Now, let mole fraction of N2 (X1) be 'n' and mole fraction of H2(X2) be '(1-n)'

M1=( 2x14=28)=mol.mass of N2

M2=(2x1=2)=mol.mass of H2

Applying formula of molar mass of mixture—

M= M1 X1 +M2 X2

4.926={ 28xn + 2x(1-n) }

solving for ‘n’ we find n=0.11

Hence the mole fraction of N2 (g)in the vessel is 0.11

Using formula d=PM/RT

Hence, M= (dxRxT)/P

M=(0.2x0.0821x300)/1

M=4.926g

Now, let mole fraction of N2 (X1) be 'n' and mole fraction of H2(X2) be '(1-n)'

M1=( 2x14=28)=mol.mass of N2

M2=(2x1=2)=mol.mass of H2

Applying formula of molar mass of mixture—

M= M1 X1 +M2 X2

4.926={ 28xn + 2x(1-n) }

solving for ‘n’ we find n=0.11

Hence the mole fraction of N2 (g)in the vessel is 0.11

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A vessel contains a mixture of H2 and N2 gas. The density of the gas mixture is 0.2g/L at 300K and 1atm. Assuming that both the gases behave ideally,the mole fraction of N2(g) in the vessel is___. (Final answer should be rounded off to two decimal places) [Given,R=0.082L.atm.mol^-1.K^-1, atomic weight of hydrogen=1 and atomic weight of nitrogen=14]? for IIT JAM 2022 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A vessel contains a mixture of H2 and N2 gas. The density of the gas mixture is 0.2g/L at 300K and 1atm. Assuming that both the gases behave ideally,the mole fraction of N2(g) in the vessel is___. (Final answer should be rounded off to two decimal places) [Given,R=0.082L.atm.mol^-1.K^-1, atomic weight of hydrogen=1 and atomic weight of nitrogen=14]? covers all topics & solutions for IIT JAM 2022 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vessel contains a mixture of H2 and N2 gas. The density of the gas mixture is 0.2g/L at 300K and 1atm. Assuming that both the gases behave ideally,the mole fraction of N2(g) in the vessel is___. (Final answer should be rounded off to two decimal places) [Given,R=0.082L.atm.mol^-1.K^-1, atomic weight of hydrogen=1 and atomic weight of nitrogen=14]?.

A vessel contains a mixture of H2 and N2 gas. The density of the gas mixture is 0.2g/L at 300K and 1atm. Assuming that both the gases behave ideally,the mole fraction of N2(g) in the vessel is___. (Final answer should be rounded off to two decimal places) [Given,R=0.082L.atm.mol^-1.K^-1, atomic weight of hydrogen=1 and atomic weight of nitrogen=14]? for IIT JAM 2022 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A vessel contains a mixture of H2 and N2 gas. The density of the gas mixture is 0.2g/L at 300K and 1atm. Assuming that both the gases behave ideally,the mole fraction of N2(g) in the vessel is___. (Final answer should be rounded off to two decimal places) [Given,R=0.082L.atm.mol^-1.K^-1, atomic weight of hydrogen=1 and atomic weight of nitrogen=14]? covers all topics & solutions for IIT JAM 2022 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vessel contains a mixture of H2 and N2 gas. The density of the gas mixture is 0.2g/L at 300K and 1atm. Assuming that both the gases behave ideally,the mole fraction of N2(g) in the vessel is___. (Final answer should be rounded off to two decimal places) [Given,R=0.082L.atm.mol^-1.K^-1, atomic weight of hydrogen=1 and atomic weight of nitrogen=14]?.

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A vessel contains a mixture of H2 and N2 gas. The density of the gas mixture is 0.2g/L at 300K and 1atm. Assuming that both the gases behave ideally,the mole fraction of N2(g) in the vessel is___. (Final answer should be rounded off to two decimal places) [Given,R=0.082L.atm.mol^-1.K^-1, atomic weight of hydrogen=1 and atomic weight of nitrogen=14]?, a detailed solution for A vessel contains a mixture of H2 and N2 gas. The density of the gas mixture is 0.2g/L at 300K and 1atm. Assuming that both the gases behave ideally,the mole fraction of N2(g) in the vessel is___. (Final answer should be rounded off to two decimal places) [Given,R=0.082L.atm.mol^-1.K^-1, atomic weight of hydrogen=1 and atomic weight of nitrogen=14]? has been provided alongside types of A vessel contains a mixture of H2 and N2 gas. The density of the gas mixture is 0.2g/L at 300K and 1atm. Assuming that both the gases behave ideally,the mole fraction of N2(g) in the vessel is___. (Final answer should be rounded off to two decimal places) [Given,R=0.082L.atm.mol^-1.K^-1, atomic weight of hydrogen=1 and atomic weight of nitrogen=14]? theory, EduRev gives you an
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Ans.Given: density of mixture=0.2g/L ,T=300K,P=1atmUsing formula d=PM/RTHence, M= (dxRxT)/PM=(0.2x0.0821x300)/1M=4.926gNow, let mole fraction of N2 (X1) be 'n' and mole fraction of H2(X2) be '(1-n)'M1=( 2x14=28)=mol.mass of N2M2=(2x1=2)=mol.mass of H2Applying formula of molar mass of mixture—M= M1 X1 +M2 X24.926={ 28xn + 2x(1-n) }solving for ‘n’ we find n=0.11Hence the mole fraction of N2 (g)in the vessel is 0.11