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Section modulus of solid circular rod of diameter d is equal to ?
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Section modulus of solid circular rod of diameter d is equal to ?
Section Modulus of Solid Circular Rod of Diameter d


The section modulus of a solid circular rod of diameter d is a measure of its strength against bending. It is a property of the cross-sectional area of the rod and is defined as the ratio of the moment of inertia of the cross-sectional area about the neutral axis to the distance from the neutral axis to the outermost point of the cross-sectional area.


Formula for Section Modulus


The formula for the section modulus of a solid circular rod of diameter d is:


Z = πd^3 / 32


where:



  • Z is the section modulus

  • d is the diameter of the rod

  • π is the mathematical constant pi (approximately 3.14159)



Explanation of Formula


The formula for the section modulus of a solid circular rod can be derived using basic calculus. The moment of inertia of the cross-sectional area of the rod about the neutral axis is given by:


I = πd^4 / 64


The distance from the neutral axis to the outermost point of the cross-sectional area is simply half the diameter of the rod, or d/2. Therefore, the section modulus can be calculated as:


Z = I / (d/2) = (πd^4 / 64) / (d/2) = πd^3 / 32


This formula shows that the section modulus of a solid circular rod increases with the cube of its diameter. Therefore, a larger diameter rod will be stronger against bending than a smaller diameter rod.
Community Answer
Section modulus of solid circular rod of diameter d is equal to ?
Pi*d^3/32
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Section modulus of solid circular rod of diameter d is equal to ?
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