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An alpha nucleus of energy 1/2mv2  bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to [2010]
  • a)
    1/Ze
  • b)
    v2
  • c)
    1/m
  • d)
    1/v4
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
An alpha nucleus of energy 1/2mv2bombards a heavy nuclear target of ch...
Kinetic energy of alpha nucleus is equall to
electrostatic potential energy of the system
of the alpha particle and the heavy nucleus.
That is,
where r0 is the distance of closest approach
Hence, correct option is (c).
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An alpha nucleus of energy 1/2mv2bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to [2010]a)1/Zeb)v2c)1/md)1/v4Correct answer is option 'C'. Can you explain this answer?
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