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A hollow sphere of radius a carries a total charge Q distributed uniformly over it's surface.A. small area dA of sphere is cutoff. Find the electric field at the centre due to the remaining sphere?
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Electric Field at the Center of a Hollow Sphere

To find the electric field at the center of a hollow sphere with a total charge Q distributed uniformly over its surface, we can use Gauss's law. Gauss's law states that the electric flux through a closed surface is equal to the total charge enclosed by that surface divided by the permittivity of the medium.

Gauss's Law:
The electric flux through a closed surface is given by:
Φ = Qenc / ε₀

Where:
Φ is the electric flux through the surface,
Qenc is the total charge enclosed by the surface,
and ε₀ is the permittivity of free space.

Applying Gauss's Law to the Hollow Sphere:

We consider a small area dA on the surface of the hollow sphere. When this area is cut off, the remaining sphere can be divided into two parts: the inner sphere and the outer spherical shell.

1. Electric Flux through the Small Area:
The electric flux through the small area dA is given by:
dΦ = E * dA

Where:
dΦ is the electric flux through the small area,
E is the electric field at the center of the sphere,
and dA is the area of the small surface element.

2. Total Charge Enclosed:
The total charge enclosed by the remaining sphere is Q - dQ, where dQ is the charge on the small area dA.

3. Electric Flux through the Remaining Sphere:
The electric flux through the remaining sphere is given by:
Φ = E * A

Where:
Φ is the electric flux through the remaining sphere,
E is the electric field at the center of the sphere,
and A is the area of the remaining sphere.

4. Applying Gauss's Law:
Using Gauss's law, we can equate the electric flux through the small area to the electric flux through the remaining sphere:
dΦ = Φ

E * dA = E * A

5. Calculating Electric Field at the Center:
Since the electric field is constant at the center of the sphere, we can cancel out the E term:
dA = A

E = Q / (4πε₀ * r²)

Where:
E is the electric field at the center of the sphere,
Q is the total charge on the sphere,
ε₀ is the permittivity of free space,
and r is the radius of the sphere.

Conclusion:
The electric field at the center of a hollow sphere with a total charge Q distributed uniformly over its surface is given by E = Q / (4πε₀ * r²).
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A hollow sphere of radius a carries a total charge Q distributed uniformly over it's surface.A. small area dA of sphere is cutoff. Find the electric field at the centre due to the remaining sphere?
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A hollow sphere of radius a carries a total charge Q distributed uniformly over it's surface.A. small area dA of sphere is cutoff. Find the electric field at the centre due to the remaining sphere? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A hollow sphere of radius a carries a total charge Q distributed uniformly over it's surface.A. small area dA of sphere is cutoff. Find the electric field at the centre due to the remaining sphere? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hollow sphere of radius a carries a total charge Q distributed uniformly over it's surface.A. small area dA of sphere is cutoff. Find the electric field at the centre due to the remaining sphere?.
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