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In case of a R firing with R2 as the variable resistance, Vgp (peak of gate voltage) and Vgt(gate triggering voltage) the value of R2 is so adjusted such that
  • a)
    Vgp = Vgt
  • b)
     Vgp > Vgt
  • c)
    Vgp < Vgt
  • d)
    Vgp = Vgt = 0
Correct answer is option 'A'. Can you explain this answer?
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In case of a R firing with R2 as the variable resistance, Vgp(peak of ...
For turning on the device, the peak of gate voltage must be equal to the gate triggering voltage.
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In case of a R firing with R2 as the variable resistance, Vgp(peak of ...
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