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A conveyor belt moves to the right with speed v=300 m/min. A pieman puts pies on the belt at a rate of 20 per minute while walking with speed 30 m/min towards a receiver at the other end. The frequency with which they are received by the stationary receiver is :
- a)26.67 / minute
- b)30 / minute
- c)22.22/minute
- d)24 / minute
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A conveyor belt moves to the right with speed v=300 m/min. A pieman pu...
This problem is a Doppler effect analogy
Where f = 20/min , v= 300 m/min
And vs = 30 m / min
Most Upvoted Answer
A conveyor belt moves to the right with speed v=300 m/min. A pieman pu...
To solve this problem, we need to consider the relative motion between the pieman and the receiver.
Let's assume the distance between the pieman and the receiver is D.
1. Time taken by the pieman to reach the receiver:
- Distance traveled by the pieman = D
- Speed of the pieman = 30 m/min
- Time taken by the pieman = D/30 min
2. Time taken for a pie to reach the receiver:
- Distance traveled by the pie on the conveyor belt = D
- Speed of the conveyor belt = 300 m/min
- Time taken for a pie to reach the receiver = D/300 min
3. Frequency of pies received by the stationary receiver:
- Frequency is defined as the number of events per unit time.
- In this case, the event is the arrival of a pie at the receiver.
- The time interval between two consecutive events is the time taken for a pie to reach the receiver.
- Therefore, the frequency is given by the reciprocal of the time taken for a pie to reach the receiver.
- Frequency = 1 / (D/300) = 300/D per minute
4. Rate at which the pieman puts pies on the belt:
- Rate is defined as the number of events per unit time.
- In this case, the event is the putting of a pie on the belt by the pieman.
- The time interval between two consecutive events is the time taken by the pieman to reach the receiver.
- Therefore, the rate is given by the reciprocal of the time taken by the pieman to reach the receiver.
- Rate = 1 / (D/30) = 30/D per minute
5. Equating the rate at which the pieman puts pies on the belt and the frequency of pies received by the stationary receiver:
- Rate = Frequency
- 30/D = 300/D
- D cancels out on both sides
- 30 = 300
- Therefore, the rate at which the pieman puts pies on the belt is equal to the frequency of pies received by the stationary receiver.
Therefore, the correct answer is option C) 22.22/min.
Let's assume the distance between the pieman and the receiver is D.
1. Time taken by the pieman to reach the receiver:
- Distance traveled by the pieman = D
- Speed of the pieman = 30 m/min
- Time taken by the pieman = D/30 min
2. Time taken for a pie to reach the receiver:
- Distance traveled by the pie on the conveyor belt = D
- Speed of the conveyor belt = 300 m/min
- Time taken for a pie to reach the receiver = D/300 min
3. Frequency of pies received by the stationary receiver:
- Frequency is defined as the number of events per unit time.
- In this case, the event is the arrival of a pie at the receiver.
- The time interval between two consecutive events is the time taken for a pie to reach the receiver.
- Therefore, the frequency is given by the reciprocal of the time taken for a pie to reach the receiver.
- Frequency = 1 / (D/300) = 300/D per minute
4. Rate at which the pieman puts pies on the belt:
- Rate is defined as the number of events per unit time.
- In this case, the event is the putting of a pie on the belt by the pieman.
- The time interval between two consecutive events is the time taken by the pieman to reach the receiver.
- Therefore, the rate is given by the reciprocal of the time taken by the pieman to reach the receiver.
- Rate = 1 / (D/30) = 30/D per minute
5. Equating the rate at which the pieman puts pies on the belt and the frequency of pies received by the stationary receiver:
- Rate = Frequency
- 30/D = 300/D
- D cancels out on both sides
- 30 = 300
- Therefore, the rate at which the pieman puts pies on the belt is equal to the frequency of pies received by the stationary receiver.
Therefore, the correct answer is option C) 22.22/min.
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A conveyor belt moves to the right with speed v=300 m/min. A pieman puts pies on the belt at a rate of 20 per minute while walking with speed 30 m/min towards a receiver at the other end. The frequency with which they are received by the stationary receiver is : a)26.67 / minuteb)30 / minutec)22.22/minuted)24 / minuteCorrect answer is option 'C'. Can you explain this answer?
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A conveyor belt moves to the right with speed v=300 m/min. A pieman puts pies on the belt at a rate of 20 per minute while walking with speed 30 m/min towards a receiver at the other end. The frequency with which they are received by the stationary receiver is : a)26.67 / minuteb)30 / minutec)22.22/minuted)24 / minuteCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A conveyor belt moves to the right with speed v=300 m/min. A pieman puts pies on the belt at a rate of 20 per minute while walking with speed 30 m/min towards a receiver at the other end. The frequency with which they are received by the stationary receiver is : a)26.67 / minuteb)30 / minutec)22.22/minuted)24 / minuteCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A conveyor belt moves to the right with speed v=300 m/min. A pieman puts pies on the belt at a rate of 20 per minute while walking with speed 30 m/min towards a receiver at the other end. The frequency with which they are received by the stationary receiver is : a)26.67 / minuteb)30 / minutec)22.22/minuted)24 / minuteCorrect answer is option 'C'. Can you explain this answer?.
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