Question Description
When a particle of mass m moves on the x-axis in a potential of the form V(x) = kx2 it performs simple harmonic motion. Thecorresponding time period is proportional to as can be seen easily using dimensional analysis. However, the motion of a particle can be periodic even when its potential energy increases on both sides of x = 0 in a way different from kx2 and its total energy is such that the particle does not escape to infinity. Consider a particle of mass m moving on the x-axis. Its potential energy is V(x) = αx4 (α > 0) for |x| near the origin and becomes a constant equal to V0 for |x| > X0 (see figure).Q.The acceleration of this particle for |x| > X0 isa)proportional to V0b)proportional to c)proportional tod)zeroCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When a particle of mass m moves on the x-axis in a potential of the form V(x) = kx2 it performs simple harmonic motion. Thecorresponding time period is proportional to as can be seen easily using dimensional analysis. However, the motion of a particle can be periodic even when its potential energy increases on both sides of x = 0 in a way different from kx2 and its total energy is such that the particle does not escape to infinity. Consider a particle of mass m moving on the x-axis. Its potential energy is V(x) = αx4 (α > 0) for |x| near the origin and becomes a constant equal to V0 for |x| > X0 (see figure).Q.The acceleration of this particle for |x| > X0 isa)proportional to V0b)proportional to c)proportional tod)zeroCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a particle of mass m moves on the x-axis in a potential of the form V(x) = kx2 it performs simple harmonic motion. Thecorresponding time period is proportional to as can be seen easily using dimensional analysis. However, the motion of a particle can be periodic even when its potential energy increases on both sides of x = 0 in a way different from kx2 and its total energy is such that the particle does not escape to infinity. Consider a particle of mass m moving on the x-axis. Its potential energy is V(x) = αx4 (α > 0) for |x| near the origin and becomes a constant equal to V0 for |x| > X0 (see figure).Q.The acceleration of this particle for |x| > X0 isa)proportional to V0b)proportional to c)proportional tod)zeroCorrect answer is option 'D'. Can you explain this answer?.

Solutions for When a particle of mass m moves on the x-axis in a potential of the form V(x) = kx2 it performs simple harmonic motion. Thecorresponding time period is proportional to as can be seen easily using dimensional analysis. However, the motion of a particle can be periodic even when its potential energy increases on both sides of x = 0 in a way different from kx2 and its total energy is such that the particle does not escape to infinity. Consider a particle of mass m moving on the x-axis. Its potential energy is V(x) = αx4 (α > 0) for |x| near the origin and becomes a constant equal to V0 for |x| > X0 (see figure).Q.The acceleration of this particle for |x| > X0 isa)proportional to V0b)proportional to c)proportional tod)zeroCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of When a particle of mass m moves on the x-axis in a potential of the form V(x) = kx2 it performs simple harmonic motion. Thecorresponding time period is proportional to as can be seen easily using dimensional analysis. However, the motion of a particle can be periodic even when its potential energy increases on both sides of x = 0 in a way different from kx2 and its total energy is such that the particle does not escape to infinity. Consider a particle of mass m moving on the x-axis. Its potential energy is V(x) = αx4 (α > 0) for |x| near the origin and becomes a constant equal to V0 for |x| > X0 (see figure).Q.The acceleration of this particle for |x| > X0 isa)proportional to V0b)proportional to c)proportional tod)zeroCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of When a particle of mass m moves on the x-axis in a potential of the form V(x) = kx2 it performs simple harmonic motion. Thecorresponding time period is proportional to as can be seen easily using dimensional analysis. However, the motion of a particle can be periodic even when its potential energy increases on both sides of x = 0 in a way different from kx2 and its total energy is such that the particle does not escape to infinity. Consider a particle of mass m moving on the x-axis. Its potential energy is V(x) = αx4 (α > 0) for |x| near the origin and becomes a constant equal to V0 for |x| > X0 (see figure).Q.The acceleration of this particle for |x| > X0 isa)proportional to V0b)proportional to c)proportional tod)zeroCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for When a particle of mass m moves on the x-axis in a potential of the form V(x) = kx2 it performs simple harmonic motion. Thecorresponding time period is proportional to as can be seen easily using dimensional analysis. However, the motion of a particle can be periodic even when its potential energy increases on both sides of x = 0 in a way different from kx2 and its total energy is such that the particle does not escape to infinity. Consider a particle of mass m moving on the x-axis. Its potential energy is V(x) = αx4 (α > 0) for |x| near the origin and becomes a constant equal to V0 for |x| > X0 (see figure).Q.The acceleration of this particle for |x| > X0 isa)proportional to V0b)proportional to c)proportional tod)zeroCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of When a particle of mass m moves on the x-axis in a potential of the form V(x) = kx2 it performs simple harmonic motion. Thecorresponding time period is proportional to as can be seen easily using dimensional analysis. However, the motion of a particle can be periodic even when its potential energy increases on both sides of x = 0 in a way different from kx2 and its total energy is such that the particle does not escape to infinity. Consider a particle of mass m moving on the x-axis. Its potential energy is V(x) = αx4 (α > 0) for |x| near the origin and becomes a constant equal to V0 for |x| > X0 (see figure).Q.The acceleration of this particle for |x| > X0 isa)proportional to V0b)proportional to c)proportional tod)zeroCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice When a particle of mass m moves on the x-axis in a potential of the form V(x) = kx2 it performs simple harmonic motion. Thecorresponding time period is proportional to as can be seen easily using dimensional analysis. However, the motion of a particle can be periodic even when its potential energy increases on both sides of x = 0 in a way different from kx2 and its total energy is such that the particle does not escape to infinity. Consider a particle of mass m moving on the x-axis. Its potential energy is V(x) = αx4 (α > 0) for |x| near the origin and becomes a constant equal to V0 for |x| > X0 (see figure).Q.The acceleration of this particle for |x| > X0 isa)proportional to V0b)proportional to c)proportional tod)zeroCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.