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A parallel plate condenser with oil between the plates (dielectric constant of oil K = 2) has a capacitance C. If the oil is removed, then capacitance of the capacitor becomes
- a)√2 C
- b)2C
- c)c/√2
- d)C/2
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A parallel plate condenser with oil between the plates (dielectric con...
When oil is placed between space of plates
When oil is removed 
... (2)
... (2)On comparing both equations, we get
C ' = C/2
C ' = C/2
Most Upvoted Answer
A parallel plate condenser with oil between the plates (dielectric con...
Explanation:
Effect of Dielectric on Capacitance:
- The capacitance of a parallel plate capacitor with a dielectric material between the plates is given by the formula: C = Kε₀A/d, where K is the dielectric constant, ε₀ is the permittivity of free space, A is the area of the plates, and d is the separation between the plates.
- When the dielectric (oil with K = 2) is present, the capacitance is C = 2ε₀A/d.
Effect of Removing the Dielectric:
- When the oil is removed, the dielectric constant becomes 1 (for air or vacuum).
- Therefore, the capacitance without the dielectric material is C' = ε₀A/d.
Comparing Capacitances:
- The ratio of the capacitance with the dielectric to the capacitance without the dielectric is:
C/C' = (2ε₀A/d) / (ε₀A/d) = 2.
- This means that the capacitance without the dielectric is half of the capacitance with the dielectric.
- Hence, the capacitance of the capacitor becomes C/2 when the oil is removed.
Therefore, the correct answer is option D (C/2).
Effect of Dielectric on Capacitance:
- The capacitance of a parallel plate capacitor with a dielectric material between the plates is given by the formula: C = Kε₀A/d, where K is the dielectric constant, ε₀ is the permittivity of free space, A is the area of the plates, and d is the separation between the plates.
- When the dielectric (oil with K = 2) is present, the capacitance is C = 2ε₀A/d.
Effect of Removing the Dielectric:
- When the oil is removed, the dielectric constant becomes 1 (for air or vacuum).
- Therefore, the capacitance without the dielectric material is C' = ε₀A/d.
Comparing Capacitances:
- The ratio of the capacitance with the dielectric to the capacitance without the dielectric is:
C/C' = (2ε₀A/d) / (ε₀A/d) = 2.
- This means that the capacitance without the dielectric is half of the capacitance with the dielectric.
- Hence, the capacitance of the capacitor becomes C/2 when the oil is removed.
Therefore, the correct answer is option D (C/2).
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