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An open glass tube is immersed in mercury in such a way that a length of 8 cm extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically up by additional 46 cm. What will be length of the air column above mercury in the tube now? (Atmospheric pressure = 76 cm of Hg) 
  • a)
    16 cm
  • b)
    22 cm
  • c)
    38 cm
  • d)
    6 cm
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
An open glass tube is immersed in mercury in such a way that a length ...
Length of the air column above mercury in the tube is, P + x = P0
⇒ P = (76 – x)
⇒ 8 × A × 76 = (76 – x) × A × (54 – x)
∴ x = 38
Thus, length of air column = 54 – 38 = 16 cm.
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Most Upvoted Answer
An open glass tube is immersed in mercury in such a way that a length ...
Given:
- Length of the open glass tube above the mercury level = 8 cm
- Additional height to which the tube is raised = 46 cm
- Atmospheric pressure = 76 cm of Hg

To find:
- Length of the air column above the mercury in the tube after raising it vertically

Solution:
When the open glass tube is immersed in mercury, the pressure inside the tube is equal to atmospheric pressure. Let's assume this pressure to be P1.

When the tube is raised vertically, the pressure inside the tube decreases due to the decrease in height of the mercury column. Let's assume the pressure inside the tube after raising it to be P2.

The pressure inside the tube is given by the equation:

P = P0 + Pm

Where,
P = Pressure inside the tube
P0 = Atmospheric pressure
Pm = Pressure due to the height of the mercury column

Calculating the pressure inside the tube before raising it:
P1 = P0 + Pm1
P1 = 76 + h1 (where h1 is the height of the mercury column)

Since the glass tube is open, the pressure inside the tube is equal to atmospheric pressure. Therefore,
P1 = P0
76 + h1 = 76
h1 = 0 cm

Calculating the pressure inside the tube after raising it:
P2 = P0 + Pm2
P2 = 76 + h2 (where h2 is the height of the mercury column after raising the tube)

The total length of the air column above the mercury level after raising the tube is given by:
Length of the glass tube - Length of the mercury column after raising = 8 cm

Therefore,
h2 = Length of the glass tube - Length of the air column above the mercury level after raising
h2 = 8 - 46
h2 = -38 cm

Since the pressure inside the tube cannot be negative, the height of the mercury column after raising the tube is 0 cm.

Therefore, the length of the air column above the mercury in the tube after raising it vertically is the same as the length of the glass tube, which is 8 cm.

Hence, the correct answer is option A.
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An open glass tube is immersed in mercury in such a way that a length of 8 cm extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically up by additional 46 cm. What will be length of the air column above mercury in the tube now? (Atmospheric pressure = 76 cm of Hg)a)16 cmb)22 cmc)38 cmd)6 cmCorrect answer is option 'A'. Can you explain this answer?
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