JEE Exam  >  JEE Questions  >  Integration of (cos5x cos4x)/(1-2cos3x)? Start Learning for Free
Integration of (cos5x cos4x)/(1-2cos3x)?
Most Upvoted Answer
Integration of (cos5x cos4x)/(1-2cos3x)?
(Cos5x Cos4x) /( 2(1- 2 Cos3x) )
=(2Cos5xCos4x)/(2(1-2Cos3x))
=[ Cos(5x+4x)+ Cos(5x-4x)]/(2(1-2Cos3x)),(since, cos(A+B) + cos(A- B)= 2CosACosB)
=(Cos9x + Cosx)/(2(1-2Cos3x))
= (Cos 5x + Cos4x)/(2(1-2Cos3x))
= (2Cos(9x/2)Cos(x/2))/(2(1-2Cos3x))
=(2Cos(9x/2)Cos(x/2))/(2(1-2(2(Cos3x/2))^2 - 1)), [since, Cos2x = 2(Cosx)^2 - 1]
=(2Cos(9x/2)Cos(x/2))/(2(1-4(Cos3x/2)^2 + 2))
= (2Cos(9x/2)Cos(x/2))/(2(3-4(Cos3x/2)^2))
multiplying by Cos3x/2 in the numerator and denominator:-
(2Cos(9x/2)Cos(x/2)Cos(3x/2))/(2(3Cos(3x/2)-4(Cos3x/2)^3)
= (Cos(9x/2)Cos(x/2)Cos(3x/2))/(3Cos(3x/2) - 4( Cos(3x/2))^3)
=(Cos(9x/2)Cos(x/2)Cos(3x/2))/(-Cos(9x/2)),[since, Cos3x = 4(cosx)^3 - 3 cosx]
=(-Cos(x/2)Cos(3x/2))
= (-1/2)(2Cos(3x/2)Cos(x/2))
=(-1/2)(Cos2x + Cosx)
Now ,on the integrating:-
(-1/2)(((Sin2x)/2) + sinx)answer
Community Answer
Integration of (cos5x cos4x)/(1-2cos3x)?
Integration of (cos5x cos4x)/(1-2cos3x)

To integrate the given expression, we can use the trigonometric identity:

cos A cos B = 1/2 [cos(A + B) + cos(A - B)]

Let's break down the expression and simplify it using this identity.

1. Simplifying the numerator:
cos5x cos4x = 1/2 [cos(5x + 4x) + cos(5x - 4x)]
= 1/2 [cos(9x) + cos(x)]

2. Simplifying the denominator:
1 - 2cos3x

3. Rewriting the expression:
(cos5x cos4x)/(1 - 2cos3x) = [1/2 (cos(9x) + cos(x))]/(1 - 2cos3x)

Now, let's proceed with the integration using a substitution method.

4. Substitute u = cos(x):
To simplify the integration, we will substitute u = cos(x). Therefore, du = -sin(x) dx.

5. Rewriting the expression with the substitution:
[1/2 (cos(9x) + cos(x))]/(1 - 2cos3x) = [1/2 (cos(9x) + u)]/(1 - 2u^3) du

6. Integrating the expression:
∫ [1/2 (cos(9x) + u)]/(1 - 2u^3) du

7. Partial fraction decomposition:
To integrate this expression, we need to decompose it into partial fractions.

Let's assume the decomposition as:
[1/2 (cos(9x) + u)]/(1 - 2u^3) = A/(1 - 2u) + B/(1 + u + u^2)

8. Find the values of A and B:
Multiply both sides by the denominator (1 - 2u)(1 + u + u^2) to get rid of the fractions.

1/2 (cos(9x) + u) = A(1 + u + u^2) + B(1 - 2u)

Comparing the coefficients of u^2, u, and constant terms, we can solve for A and B.

9. Perform the partial fraction decomposition:
Once we have the values of A and B, we can rewrite the expression using the partial fraction decomposition.

10. Integrating the partial fractions:
Now, we can integrate the partial fractions separately.

11. Substitute back the value of u:
After integrating, substitute back u = cos(x) to obtain the final result.

12. Write the final result:
The final result will be in terms of x after substituting back the value of u.

By following these steps, you can integrate the given expression.
Explore Courses for JEE exam
Integration of (cos5x cos4x)/(1-2cos3x)?
Question Description
Integration of (cos5x cos4x)/(1-2cos3x)? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Integration of (cos5x cos4x)/(1-2cos3x)? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Integration of (cos5x cos4x)/(1-2cos3x)?.
Solutions for Integration of (cos5x cos4x)/(1-2cos3x)? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Integration of (cos5x cos4x)/(1-2cos3x)? defined & explained in the simplest way possible. Besides giving the explanation of Integration of (cos5x cos4x)/(1-2cos3x)?, a detailed solution for Integration of (cos5x cos4x)/(1-2cos3x)? has been provided alongside types of Integration of (cos5x cos4x)/(1-2cos3x)? theory, EduRev gives you an ample number of questions to practice Integration of (cos5x cos4x)/(1-2cos3x)? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev