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A magnetic moment of 1.73 BM will be shown by one among following.
- a)[Ni(CN)4]2-
- b)TiCI4
- c)[CoCI6]4-
- d)[Cu(NH3)4]2+
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A magnetic moment of 1.73 BM will be shown by one among following.a)[N...
A magnetic moment of 1.73 BM corresponds to one unpaired electron. Among the given, (a) and (b) are diamagnetic and (c) is paramagnetic with 3 unpaired electrons (3d7 configuration).
Most Upvoted Answer
A magnetic moment of 1.73 BM will be shown by one among following.a)[N...
The Correct Answer is Option D: [Cu(NH3)4]2
Explanation:
Magnetic Moment:
The magnetic moment is a property of a substance which arises due to the presence of unpaired electrons. It is a measure of the strength and direction of the magnetic field produced by the substance.
Magnetic Moment Units:
The magnetic moment is typically measured in units of Bohr magneton (BM) or Tesla-meter squared (T m^2).
Determining the Magnetic Moment:
To determine the magnetic moment of a substance, we need to consider the number of unpaired electrons and their spin orientation.
[Ni(CN)4]2-
- Nickel is in the +2 oxidation state in this compound, and it has a d8 electronic configuration.
- CN- is a strong field ligand that causes pairing of electrons in the d orbitals of the metal ion.
- Therefore, [Ni(CN)4]2- has a diamagnetic nature and does not possess any unpaired electrons.
- Hence, the magnetic moment of [Ni(CN)4]2- is 0 BM.
TiCl4
- Titanium is in the +4 oxidation state in this compound and has a d0 electronic configuration.
- Since there are no unpaired electrons present, TiCl4 is diamagnetic.
- Hence, the magnetic moment of TiCl4 is 0 BM.
[CoCl6]4-
- Cobalt is in the +3 oxidation state in this complex and has a d6 electronic configuration.
- The weak field ligands do not cause pairing of electrons in the d orbitals.
- [CoCl6]4- has four unpaired electrons, and each electron contributes 1 BM to the magnetic moment.
- Hence, the magnetic moment of [CoCl6]4- is 4 BM.
[Cu(NH3)4]2
- Copper is in the +2 oxidation state in this complex and has a d9 electronic configuration.
- The weak field ligands do not cause pairing of electrons in the d orbitals.
- [Cu(NH3)4]2 has one unpaired electron, contributing 1 BM to the magnetic moment.
- Hence, the magnetic moment of [Cu(NH3)4]2 is 1 BM.
Conclusion:
Among the given options, only [Cu(NH3)4]2 has a magnetic moment of 1.73 BM. Therefore, the correct answer is option D.
Explanation:
Magnetic Moment:
The magnetic moment is a property of a substance which arises due to the presence of unpaired electrons. It is a measure of the strength and direction of the magnetic field produced by the substance.
Magnetic Moment Units:
The magnetic moment is typically measured in units of Bohr magneton (BM) or Tesla-meter squared (T m^2).
Determining the Magnetic Moment:
To determine the magnetic moment of a substance, we need to consider the number of unpaired electrons and their spin orientation.
[Ni(CN)4]2-
- Nickel is in the +2 oxidation state in this compound, and it has a d8 electronic configuration.
- CN- is a strong field ligand that causes pairing of electrons in the d orbitals of the metal ion.
- Therefore, [Ni(CN)4]2- has a diamagnetic nature and does not possess any unpaired electrons.
- Hence, the magnetic moment of [Ni(CN)4]2- is 0 BM.
TiCl4
- Titanium is in the +4 oxidation state in this compound and has a d0 electronic configuration.
- Since there are no unpaired electrons present, TiCl4 is diamagnetic.
- Hence, the magnetic moment of TiCl4 is 0 BM.
[CoCl6]4-
- Cobalt is in the +3 oxidation state in this complex and has a d6 electronic configuration.
- The weak field ligands do not cause pairing of electrons in the d orbitals.
- [CoCl6]4- has four unpaired electrons, and each electron contributes 1 BM to the magnetic moment.
- Hence, the magnetic moment of [CoCl6]4- is 4 BM.
[Cu(NH3)4]2
- Copper is in the +2 oxidation state in this complex and has a d9 electronic configuration.
- The weak field ligands do not cause pairing of electrons in the d orbitals.
- [Cu(NH3)4]2 has one unpaired electron, contributing 1 BM to the magnetic moment.
- Hence, the magnetic moment of [Cu(NH3)4]2 is 1 BM.
Conclusion:
Among the given options, only [Cu(NH3)4]2 has a magnetic moment of 1.73 BM. Therefore, the correct answer is option D.
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A magnetic moment of 1.73 BM will be shown by one among following.a)[Ni(CN)4]2-b)TiCI4c)[CoCI6]4-d)[Cu(NH3)4]2+Correct answer is option 'D'. Can you explain this answer?
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