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For the circuit shown below, the capacitor is initially charged to a voltage of Vo with the upper plate positive. Switch is closed at t=0. The peak value of the current through the diode is​
  • a)
    Vo/C
  • b)
    Vo/R
  • c)
    Vo
  • d)
    Vo/(RC)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
For the circuit shown below, the capacitor is initially charged to a v...
When switch is closed, the equation is
Ri + 1/C ∫idt = 0 (Voltage across capacitor cannot change instantaneously)
Solution of the above equation gives, Vo/R at t= 0.
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For the circuit shown below, the capacitor is initially charged to a voltage of Vo with the upper plate positive. Switch is closed at t=0. The peak value of the current through the diode is​a)Vo/Cb)Vo/Rc)Vod)Vo/(RC)Correct answer is option 'B'. Can you explain this answer?
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