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The ionization energy of hydrogen atom is 13.6 ev the energy required to excite the electron in hydrogen atom from ground state to to first excited state is?
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The ionization energy of hydrogen atom is 13.6 ev the energy required ...
N=1 me -13.6ev and n=2 me -3.4ev then excitation energy = final - initial energy then 10.2ev Ans.
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The ionization energy of hydrogen atom is 13.6 ev the energy required ...


Calculating Energy Required to Excite Electron in Hydrogen Atom

To calculate the energy required to excite the electron in a hydrogen atom from the ground state to the first excited state, we need to understand the concept of ionization energy and energy levels.

Ionization Energy:
- The ionization energy of a hydrogen atom is 13.6 eV, which is the energy required to completely remove an electron from the atom.

Energy Levels in Hydrogen Atom:
- In a hydrogen atom, the electron can occupy different energy levels. The ground state is the lowest energy level, while the first excited state is the next higher energy level.

Energy Difference between Ground State and First Excited State:
- The energy required to excite the electron from the ground state to the first excited state is equal to the difference in energy between these two states.
- This energy difference can be calculated using the formula: ΔE = E_final - E_initial.

Calculation:
- E_initial (ground state) = 13.6 eV (ionization energy)
- E_final (first excited state) = E_initial / n^2, where n is the energy level (n=1 for ground state, n=2 for first excited state)
- E_final = 13.6 eV / 2^2 = 13.6 eV / 4 = 3.4 eV

Energy Required to Excite Electron:
- The energy required to excite the electron from the ground state to the first excited state is 3.4 eV.

Therefore, the energy required to excite the electron in a hydrogen atom from the ground state to the first excited state is 3.4 eV.
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The ionization energy of hydrogen atom is 13.6 ev the energy required to excite the electron in hydrogen atom from ground state to to first excited state is?
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