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How many sulphur atoms present in 2N 500 ml of sulphuric acid?
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How many sulphur atoms present in 2N 500 ml of sulphuric acid?
One sulfuric (H2SO4) molecule has 2 hydrogen atoms, 1 sulfur atom, and 4 oxygen atoms. You can also say one mole of sulfuric acid has two mols of hydrogen atoms, 1 mol of sulfur atoms, and 4 moles of oxygen atoms. So in total, we have 7 mols of atoms. But that's in 1 mol of sulfuric acid.
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How many sulphur atoms present in 2N 500 ml of sulphuric acid?
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How many sulphur atoms present in 2N 500 ml of sulphuric acid?
Sulphur atoms in 2N 500 ml of sulphuric acid
To determine the number of sulphur atoms present in 2N 500 ml of sulphuric acid, we need to understand the concept of molarity and the molecular formula of sulphuric acid.

Molarity of sulphuric acid:
- Sulphuric acid has a molecular formula of H2SO4.
- In 2N solution, the concentration of sulphuric acid is 2 moles per liter (2N = 2 mol/L).

Calculating moles of sulphuric acid:
- Given that the volume is 500 ml (0.5 L) and the concentration is 2N, we can calculate the moles of sulphuric acid:
Molarity (M) = moles (mol) / volume (L)
2 = moles / 0.5
Moles = 2 x 0.5 = 1 mol

Number of sulphur atoms in sulphuric acid:
- In one molecule of H2SO4, there is 1 sulphur atom.
- Therefore, in 1 mole of H2SO4, there is 1 mole of sulphur atoms.

Calculating sulphur atoms in 1 mole of H2SO4:
- Avogadro's number states that 1 mole of any substance contains 6.022 x 10^23 particles.
- So, 1 mole of sulphur atoms in H2SO4 contains 6.022 x 10^23 atoms.

Calculating sulphur atoms in 1 mole of sulphuric acid:
- Since there is 1 mole of sulphur atoms in 1 mole of H2SO4,
- There are 6.022 x 10^23 sulphur atoms in 1 mole of sulphuric acid.
Therefore, in 2N 500 ml of sulphuric acid, which contains 1 mole of H2SO4, there are 6.022 x 10^23 sulphur atoms.
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How many sulphur atoms present in 2N 500 ml of sulphuric acid?
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