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? A ball of mass 0.25 kg attached to the end of a string of length 1.96 is moving in a a horizontal circle the string will break if the tension is more than 25 Newton what is the maximum speed with which the ball can be moved? Answer is 14m/s can any one solve it.?
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? A ball of mass 0.25 kg attached to the end of a string of length 1.9...
Problem Analysis:
We have a ball moving in a horizontal circle attached to a string. The tension in the string should not exceed 25 Newtons, otherwise, the string will break. We need to find the maximum speed at which the ball can be moved without breaking the string.

Solution:

To solve this problem, we need to consider the forces acting on the ball and use the concept of centripetal force.

1. Centripetal Force:
The centripetal force is the force that keeps an object moving in a circular path. It is always directed towards the center of the circle. In this case, the centripetal force is provided by the tension in the string.

2. Tension in the String:
The tension in the string is the force that is transmitted through the string when it is pulled taut. In this case, the tension in the string should not exceed 25 Newtons to avoid breaking the string.

3. Centripetal Force Equation:
The centripetal force can be calculated using the following equation:
F = m * a
where F is the centripetal force, m is the mass of the ball, and a is the acceleration of the ball towards the center of the circle.

4. Acceleration in Circular Motion:
The acceleration of an object moving in a circular path can be calculated using the following equation:
a = v^2 / r
where v is the velocity of the object and r is the radius of the circular path.

5. Maximum Speed:
To find the maximum speed at which the ball can be moved without breaking the string, we need to find the velocity at which the tension in the string is equal to 25 Newtons. We can set up the following equation:
F = m * a = m * (v^2 / r)
25 = 0.25 * (v^2 / 1.96)

6. Solving for Velocity:
Simplifying the equation, we have:
25 = (0.25 * v^2) / 1.96
Multiplying both sides by 1.96:
49 = 0.25 * v^2
Dividing both sides by 0.25:
196 = v^2
Taking the square root of both sides:
v = √196
v ≈ 14 m/s

Therefore, the maximum speed at which the ball can be moved without breaking the string is approximately 14 m/s.
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? A ball of mass 0.25 kg attached to the end of a string of length 1.9...
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? A ball of mass 0.25 kg attached to the end of a string of length 1.96 is moving in a a horizontal circle the string will break if the tension is more than 25 Newton what is the maximum speed with which the ball can be moved? Answer is 14m/s can any one solve it.?
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? A ball of mass 0.25 kg attached to the end of a string of length 1.96 is moving in a a horizontal circle the string will break if the tension is more than 25 Newton what is the maximum speed with which the ball can be moved? Answer is 14m/s can any one solve it.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about ? A ball of mass 0.25 kg attached to the end of a string of length 1.96 is moving in a a horizontal circle the string will break if the tension is more than 25 Newton what is the maximum speed with which the ball can be moved? Answer is 14m/s can any one solve it.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for ? A ball of mass 0.25 kg attached to the end of a string of length 1.96 is moving in a a horizontal circle the string will break if the tension is more than 25 Newton what is the maximum speed with which the ball can be moved? Answer is 14m/s can any one solve it.?.
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