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A body starts from rest with constant acceleration a it's velocity after n second is V. The displacement of body in last two seconds is- ?
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A body starts from rest with constant acceleration a it's velocity aft...
A particle starts from rest so, initial velocity of particle , u = 0
particle acceleration with constant acceleration a
So, particle must follow all kinematical equations .
I mean, S = ut + 1/2at^2
At u = 0, S = 1/2at^2
Here S is displacement during t time .
∴ displacement in last 2 sec = distance travelled in n sec- distance travelled in (n -2) sec
=  = 1/2 an^2 - 1/2a(n -2)^2
= 1/2 a (n^2 - n^2 + 4n - 4)
= a (2n -2)
So, displacement in last 2 sec = a(2n - 2)
A/C to question,
Final velocity = v
Time = t
Acceleration = a
Then, use formula,
v = u + at
initial rest so, u = 0
v = a x n ⇒a = v/n
Now, displacement in last 2 sec = v/n(2n - 2) = 2v - 2v/n
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A body starts from rest with constant acceleration a it's velocity after n second is V. The displacement of body in last two seconds is- ?
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