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A mass ‘m’ moves with a velocity ‘v’ and collides inelastically with another identical mass . After collision the 1st mass moves with velocity 
in a direction perpendicular to the initial direction of motion. Find the speed of the 2nd mass after collision.
in a direction perpendicular to the initial direction of motion. Find the speed of the 2nd mass after collision.
- a)
- b)v
- c)
- d)
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A mass ‘m’ moves with a velocity ‘v’ and colli...
In x-direction, mv = mv1 cosθ ...(1) where v1 is the velocity of second mass
In y-direction, 
Squaring and adding eqns. (1) and (2)
Most Upvoted Answer
A mass ‘m’ moves with a velocity ‘v’ and colli...
Option (D) is the correct answer.
Here is the explanation :
Initial momentum of the particles = mv +0 = mv
which is along x-axis.
After collision the net momentum of the system should also be equal to mv and along x-axis only
Thus,
the 2nd particle should have two velocities, one equal to v/(root 3) opposite to the velocity of first particle after collision
And other velocity equal to v along x axis
Thus net speed of 2nd particle after collision is equal to magnitude of [ v/(root 3)j + v i]
Which is equal to 2v/(root3)
Here is the explanation :
Initial momentum of the particles = mv +0 = mv
which is along x-axis.
After collision the net momentum of the system should also be equal to mv and along x-axis only
Thus,
the 2nd particle should have two velocities, one equal to v/(root 3) opposite to the velocity of first particle after collision
And other velocity equal to v along x axis
Thus net speed of 2nd particle after collision is equal to magnitude of [ v/(root 3)j + v i]
Which is equal to 2v/(root3)
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A mass ‘m’ moves with a velocity ‘v’ and collides inelastically with another identical mass . After collision the 1st mass moves with velocityin a direction perpendicular to the initial direction of motion. Find the speed of the 2nd mass after collision.a)b)vc)d)Correct answer is option 'D'. Can you explain this answer?
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