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Aldehydes are prepared by reducing nitriles to corresponding imines with stannous chloride in the presence of hydrochloric acid. This reaction is called?
  • a)
    Gatterman – Koch reaction
  • b)
    Etard reaction.
  • c)
    Stephen reaction
  • d)
    Friedel – Crafts reaction
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Aldehydes are prepared by reducing nitriles to corresponding imines wi...
Reaction for preparation of aldehydes by reducing RCN is stephens Reaction.
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Aldehydes are prepared by reducing nitriles to corresponding imines wi...
The correct answer is option 'C' - Stephen reaction.

The Stephen reaction is a method used to prepare aldehydes from nitriles. It involves the reduction of nitriles to imines using stannous chloride (SnCl2) in the presence of hydrochloric acid (HCl). The imines obtained from this reaction can be further hydrolyzed to yield aldehydes.

Here is a detailed explanation of the Stephen reaction:

1. Reaction Equation:
The reaction can be represented by the following equation:
RCN + SnCl2 + HCl → RCH=NCl + SnCl4

2. Role of Stannous Chloride:
Stannous chloride (SnCl2) acts as a reducing agent in the reaction. It converts the nitrile group (RCN) into an imine group (RCH=NCl). The reduction involves the transfer of a hydride ion (H-) from SnCl2 to the nitrile carbon, resulting in the formation of the imine.

3. Role of Hydrochloric Acid:
Hydrochloric acid (HCl) serves as a catalyst in the reaction. It helps in the activation of the nitrile group by protonating it, making it more susceptible to reduction. The acid also helps in maintaining the acidic conditions required for the reaction to proceed.

4. Formation of Imines:
In the presence of SnCl2 and HCl, the nitrile group undergoes nucleophilic addition with SnCl2. This leads to the formation of an intermediate complex, followed by the elimination of a chloride ion. The resulting imine (RCH=NCl) is stabilized by resonance, where the nitrogen atom donates its lone pair of electrons to the carbon-nitrogen double bond.

5. Hydrolysis to Aldehydes:
The imines obtained from the Stephen reaction can be hydrolyzed to yield aldehydes. This is achieved by treating the imine with a suitable reagent, such as dilute acid or base. The hydrolysis reaction involves the cleavage of the carbon-nitrogen double bond, resulting in the formation of an aldehyde.

In summary, the Stephen reaction is a method used to prepare aldehydes from nitriles. It involves the reduction of nitriles to imines using stannous chloride in the presence of hydrochloric acid. The imines obtained can be further hydrolyzed to yield aldehydes.
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Aldehydes are prepared by reducing nitriles to corresponding imines with stannous chloride in the presence of hydrochloric acid. This reaction is called?a)Gatterman – Koch reactionb)Etard reaction.c)Stephen reactiond)Friedel – Crafts reactionCorrect answer is option 'C'. Can you explain this answer?
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Aldehydes are prepared by reducing nitriles to corresponding imines with stannous chloride in the presence of hydrochloric acid. This reaction is called?a)Gatterman – Koch reactionb)Etard reaction.c)Stephen reactiond)Friedel – Crafts reactionCorrect answer is option 'C'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Aldehydes are prepared by reducing nitriles to corresponding imines with stannous chloride in the presence of hydrochloric acid. This reaction is called?a)Gatterman – Koch reactionb)Etard reaction.c)Stephen reactiond)Friedel – Crafts reactionCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Aldehydes are prepared by reducing nitriles to corresponding imines with stannous chloride in the presence of hydrochloric acid. This reaction is called?a)Gatterman – Koch reactionb)Etard reaction.c)Stephen reactiond)Friedel – Crafts reactionCorrect answer is option 'C'. Can you explain this answer?.
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