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General Solution of (ex + e-x) dy - (ex - e-x) dx = 0
- a)y = log(e2x+ e−x) + C
- b)y = log(ex+ e−x) + C
- c)y = (ex+ e−x) + C
- d)y = log(e−2x+ e−x) + C
Correct answer is option 'B'. Can you explain this answer?
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General Solution of (ex+ e-x) dy - (ex- e-x) dx = 0a)y=log(e2x+e&minus...
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General Solution of (ex+ e-x) dy - (ex- e-x) dx = 0a)y=log(e2x+e&minus...
General Solution of the given differential equation:
- To find the general solution of the given differential equation, start by rearranging the equation in the form of dy/dx.
- The given differential equation is: (ex+ e-x) dy - (ex- e-x) dx = 0
- Rearranging the equation gives: dy/dx = (ex- e-x) / (ex+ e-x)
Integrating the equation:
- To solve this differential equation, separate the variables and integrate both sides.
- Integrate the left side with respect to y and the right side with respect to x.
- Integrate (ex+ e-x) dy = Integrate (ex- e-x) dx
Applying Integration:
- The integral of (ex+ e-x) dy is y = log|ex+e-x| + C1, where C1 is the constant of integration.
- The integral of (ex- e-x) dx is x = log|ex-e-x| + C2, where C2 is the constant of integration.
General Solution:
- Combining the results from the integrations, the general solution of the given differential equation is:
- y = log(ex+e-x) + C1
- This is the general solution for the given differential equation.
- To find the general solution of the given differential equation, start by rearranging the equation in the form of dy/dx.
- The given differential equation is: (ex+ e-x) dy - (ex- e-x) dx = 0
- Rearranging the equation gives: dy/dx = (ex- e-x) / (ex+ e-x)
Integrating the equation:
- To solve this differential equation, separate the variables and integrate both sides.
- Integrate the left side with respect to y and the right side with respect to x.
- Integrate (ex+ e-x) dy = Integrate (ex- e-x) dx
Applying Integration:
- The integral of (ex+ e-x) dy is y = log|ex+e-x| + C1, where C1 is the constant of integration.
- The integral of (ex- e-x) dx is x = log|ex-e-x| + C2, where C2 is the constant of integration.
General Solution:
- Combining the results from the integrations, the general solution of the given differential equation is:
- y = log(ex+e-x) + C1
- This is the general solution for the given differential equation.
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General Solution of (ex+ e-x) dy - (ex- e-x) dx = 0a)y=log(e2x+e−x)+Cb)y=log(ex+e−x)+Cc)y=(ex+e−x)+Cd)y=log(e−2x+e−x)+CCorrect answer is option 'B'. Can you explain this answer?
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General Solution of (ex+ e-x) dy - (ex- e-x) dx = 0a)y=log(e2x+e−x)+Cb)y=log(ex+e−x)+Cc)y=(ex+e−x)+Cd)y=log(e−2x+e−x)+CCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about General Solution of (ex+ e-x) dy - (ex- e-x) dx = 0a)y=log(e2x+e−x)+Cb)y=log(ex+e−x)+Cc)y=(ex+e−x)+Cd)y=log(e−2x+e−x)+CCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for General Solution of (ex+ e-x) dy - (ex- e-x) dx = 0a)y=log(e2x+e−x)+Cb)y=log(ex+e−x)+Cc)y=(ex+e−x)+Cd)y=log(e−2x+e−x)+CCorrect answer is option 'B'. Can you explain this answer?.
General Solution of (ex+ e-x) dy - (ex- e-x) dx = 0a)y=log(e2x+e−x)+Cb)y=log(ex+e−x)+Cc)y=(ex+e−x)+Cd)y=log(e−2x+e−x)+CCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about General Solution of (ex+ e-x) dy - (ex- e-x) dx = 0a)y=log(e2x+e−x)+Cb)y=log(ex+e−x)+Cc)y=(ex+e−x)+Cd)y=log(e−2x+e−x)+CCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for General Solution of (ex+ e-x) dy - (ex- e-x) dx = 0a)y=log(e2x+e−x)+Cb)y=log(ex+e−x)+Cc)y=(ex+e−x)+Cd)y=log(e−2x+e−x)+CCorrect answer is option 'B'. Can you explain this answer?.
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