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Which of the following factors govern solubility of two non-ferrous metals both inliquid state, as well as in solid state?
1. Crystal structure
2. Relative size factor
3. Chemical-affinity factor
4. Relative valence factor
Select the correct answer using the codes given below:
Codes:
1. Crystal structure
2. Relative size factor
3. Chemical-affinity factor
4. Relative valence factor
Select the correct answer using the codes given below:
Codes:
- a)1, 2 and 3
- b)2, 3 and 4
- c)1 and 4
- d)1, 2, 3 and 4
Correct answer is option 'D'. Can you explain this answer?
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Factors Governing Solubility of Non-Ferrous Metals:
1. Crystal Structure:
- The crystal structure of non-ferrous metals plays a crucial role in determining their solubility in both liquid and solid states. Different crystal structures can affect the arrangement of atoms and the ability of metals to dissolve in each other.
2. Relative Size Factor:
- The relative size factor between two non-ferrous metals influences their solubility. Metals with similar atomic sizes are more likely to be soluble in each other, while metals with significantly different sizes may have limited solubility.
3. Chemical-Affinity Factor:
- The chemical affinity between two non-ferrous metals is another important factor governing their solubility. Metals with similar chemical properties and bonding tendencies are more likely to dissolve in each other, while metals with different chemical affinities may not mix well.
4. Relative Valence Factor:
- The relative valence factor, which refers to the number of electrons in the outermost shell of the atoms, also influences the solubility of non-ferrous metals. Metals with similar valence electron configurations are more likely to be soluble in each other, while those with different valence factors may have limited solubility.
In conclusion, all four factors - crystal structure, relative size factor, chemical-affinity factor, and relative valence factor - play a significant role in determining the solubility of non-ferrous metals in both liquid and solid states. Understanding these factors is essential for predicting and controlling the behavior of metal mixtures in various applications.
1. Crystal Structure:
- The crystal structure of non-ferrous metals plays a crucial role in determining their solubility in both liquid and solid states. Different crystal structures can affect the arrangement of atoms and the ability of metals to dissolve in each other.
2. Relative Size Factor:
- The relative size factor between two non-ferrous metals influences their solubility. Metals with similar atomic sizes are more likely to be soluble in each other, while metals with significantly different sizes may have limited solubility.
3. Chemical-Affinity Factor:
- The chemical affinity between two non-ferrous metals is another important factor governing their solubility. Metals with similar chemical properties and bonding tendencies are more likely to dissolve in each other, while metals with different chemical affinities may not mix well.
4. Relative Valence Factor:
- The relative valence factor, which refers to the number of electrons in the outermost shell of the atoms, also influences the solubility of non-ferrous metals. Metals with similar valence electron configurations are more likely to be soluble in each other, while those with different valence factors may have limited solubility.
In conclusion, all four factors - crystal structure, relative size factor, chemical-affinity factor, and relative valence factor - play a significant role in determining the solubility of non-ferrous metals in both liquid and solid states. Understanding these factors is essential for predicting and controlling the behavior of metal mixtures in various applications.
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Which of the following factors govern solubility of two non-ferrous metals both inliquid state, as well as in solid state?1. Crystal structure2. Relative size factor3. Chemical-affinity factor4. Relative valence factorSelect the correct answer using the codes given below:Codes:a)1, 2 and 3b)2, 3 and 4c)1 and 4d)1, 2, 3 and 4Correct answer is option 'D'. Can you explain this answer?
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Which of the following factors govern solubility of two non-ferrous metals both inliquid state, as well as in solid state?1. Crystal structure2. Relative size factor3. Chemical-affinity factor4. Relative valence factorSelect the correct answer using the codes given below:Codes:a)1, 2 and 3b)2, 3 and 4c)1 and 4d)1, 2, 3 and 4Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Which of the following factors govern solubility of two non-ferrous metals both inliquid state, as well as in solid state?1. Crystal structure2. Relative size factor3. Chemical-affinity factor4. Relative valence factorSelect the correct answer using the codes given below:Codes:a)1, 2 and 3b)2, 3 and 4c)1 and 4d)1, 2, 3 and 4Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following factors govern solubility of two non-ferrous metals both inliquid state, as well as in solid state?1. Crystal structure2. Relative size factor3. Chemical-affinity factor4. Relative valence factorSelect the correct answer using the codes given below:Codes:a)1, 2 and 3b)2, 3 and 4c)1 and 4d)1, 2, 3 and 4Correct answer is option 'D'. Can you explain this answer?.
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