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volume of vapour obtainedc at S.T.P by complete evaporation of 0.2g of a substance ,mol mass=112g\mole is ?
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volume of vapour obtainedc at S.T.P by complete evaporation of 0.2g o...
Calculating the Volume of Vapour at S.T.P
1. Given Data:
- Mass of the substance = 0.2g
- Molar mass of the substance = 112g/mol
2. Calculating Moles:
- Moles = Mass / Molar mass
- Moles = 0.2g / 112g/mol
- Moles = 0.00179 mol
3. Using Ideal Gas Law:
- PV = nRT
- At S.T.P, P = 1 atm, T = 273 K, R = 0.0821 L.atm/mol.K
- V = nRT / P
- V = 0.00179 mol * 0.0821 L.atm/mol.K * 273 K / 1 atm
- V = 0.0405 L
4. Final Answer:
The volume of vapour obtained at S.T.P by the complete evaporation of 0.2g of the substance is 0.0405 liters.
Community Answer
volume of vapour obtainedc at S.T.P by complete evaporation of 0.2g o...
0.04 L
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volume of vapour obtainedc at S.T.P by complete evaporation of 0.2g of a substance ,mol mass=112g\mole is ?
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